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Hunter-Best [27]
3 years ago
10

The log-likelihood statistic is analogous to the residual sum of squares in multiple regression in the sense that it is an indic

ator of how much unexplained information there is after the model has been fitted. It, therefore, follows that ____ values of the log-likelihood statistic indicate poorly fitting statistical models.
Mathematics
1 answer:
ss7ja [257]3 years ago
5 0

Answer:

A. small

Step-by-step explanation:

According to a different source, these are the options that come with this question:

A. small

B. large

The log-likelihood statistic is an indicator of how much explained information there is after the model has been fitted. This means that the higher the log-likelihood, the better our model fits the available data. In other words, it also means that the small values of the log-likelihood statistic indicate poorly fitting statistical models.

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Lina20 [59]

Answer:

To select a <u>stratified</u> random sample, first classify the population into groups of similar individuals, then choose a separate SRS in each group and combine these SRS to form the full sample

Step-by-step explanation:

Stratified random sampling involved dividing the population into small groups of similar individuals (called strata) and then from among those groups, a stratified random sample is selected and then, all these samples are combined to form the full sample. Hence, the missing word in this sentence is <u>stratified.</u>

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3 years ago
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!
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Answer: will be A

Step-by-step explanation:

4 0
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ivolga24 [154]

Given:

Two jugs are similar. The smaller jug has radius 4 cm and the bigger jug has radius 6 cm and surface area 125 cm².

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The area of the smaller jug.

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If two figures are similar, then the ratio of their areas is proportional to the square of the corresponding sides of the figures.

Two jugs are similar. So,

\dfrac{\text{Area of smaller jug}}{\text{Area of bigger jug}}=\dfrac{(\text{Radius of smaller jug})^2}{(\text{Radius of bigger jug})^2}

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\text{Area of smaller jug}\approx 55.56

Therefore, the area of the smaller jug is about 55.56 cm².

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Answer:

Step-by-step explanation:

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