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3 years ago

6. Jack is building a rectangular dog pen that he wishes to enclose. The width of the pen is 2

Mathematics

1 answer:

san4es73 [151]3 years ago

3 0

Answer:

Pretty sure the width is 3 and the length is 5.

Step-by-step explanation:

What are the multiples of 15 (3 and 5) those are the only multiples besides 1 and 15. If that makes sense.

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<img src="https://tex.z-dn.net/?f=%283%20%5Cfrac%7B2%7D%7B5%7D%20%20-%201%20%5Cfrac%7B3%7D%7B10%7D%20%29%20%5Cdiv%201%20%5Cfrac%

nata0808 [166]

Answer:

$\frac{3}{2}$

Step-by-step explanation:

$[\frac{2}{5}-\frac{3}{10}+(3-1)]\div 1\frac{2}{5}\\\\=(\frac{4}{10}-\frac{3}{10}+2)\div\frac{5+2}{5}\\\\=(\frac{1}{10}+2)\div \frac{7}{5}\\\\=(\frac{2\cdot10+1}{10})\div \frac{7}{5}\\\\=\frac{21}{10}\div \frac{7}{5}\\\\=\frac{21}{10}\times \frac{5}{7}\\\\=\frac{21\cdot5}{10\cdot7}\\\\=\frac{3}{2}$

7 0

3 years ago

Pls pls pls help meee plssss

umka21 [38]

Answer:

x = 5 or 1

Step-by-step explanation:

Square both sides to get

x^2 - 6x + 9 = 4 now subtract four from both sides

x^2 -6x+5 = 0 now factor ( or use quadratic formula)

(x-5)(x-1) = 0 so x = 5 or 1

6 0

2 years ago

Please help with these partial fractions!!!

VARVARA [1.3K]

a. Factorize the denominator:

$\dfrac{x+14}{x^2-2x-8}=\dfrac{x+14}{(x-4)(x+2)}$

Then we're looking for $a,b$ such that

$\dfrac{x+14}{x^2-2x-8}=\dfrac a{x-4}+\dfrac b{x+2}$

$\implies x+14=a(x+2)+b(x-4)$

If $x=4$ , then $18=6a\implies a=3$ ; if $x=-2$ , then $12=-6b\implies b=-2$ . So we have

$\dfrac{x+14}{x^2-2x-8}=\dfrac3{x-4}-\dfrac2{x+2}$

as required.

b. Same setup as in (a):

$\dfrac{-3x^2+5x+6}{x^3+x^2}=\dfrac{-3x^2+5x+6}{x^2(x+1)}$

We want to find $a,b,c$ such that

$\dfrac{-3x^2+5x+6}{x^2(x+1)}=\dfrac ax+\dfrac b{x^2}+\dfrac c{x+1}$

Quick aside: for the second term, since the denominator has degree 2, we should be looking for another constant $b'$ such that the numerator of the second term is $b'x+b$ . We always want the polynomial in the numerator to have degree 1 less than the degree of the denominator. But we would end up determining $b'=0$ anyway.

$\implies-3x^2+5x+6=ax(x+1)+b(x+1)+cx^2$

If $x=0$ , then $b=6$ ; if $x=-1$ , then $c=-2$ . Expanding everything on the right then gives

$-3x^2+5x+6=ax^2+ax+bx+b+cx^2=(a-2)x^2+(a+6)x+6$

which tells us $a-2=-3$ and $a+6=5$ ; in both cases, we get $a=-1$ . Then

$\dfrac{-3x^2+5x+6}{x^2(x+1)}=-\dfrac1x+\dfrac6{x^2}-\dfrac2{x+1}$

as required.

5 0

4 years ago

18. Dylan's mother tells Dylan he must spend

Klio2033 [76]

Answer:

Dylan is playing anywhere from 3.5 hours to 9.5 hours of electronic games on week days.

Step-by-step explanation:

(least estimated amount of hours played each week) 13-9.5=3.5

(highest estimated amount of hours played each week)19-9.5=9.5

If I helped you please let me know with a thank you, rating or brainly

<3Miss Hawaii<3

3 0

3 years ago

Number 1 so I can make sure I'm right

SSSSS [86.1K]

Answer:

228.36 ft^2

Step-by-step explanation:

1. The total surface area is the area of two trapezoids and 4 rectangles. The rectangles all have the same width, so we can figure their area by finding their total length: the perimeter of the trapezoid.

rectangle area

The perimeter of the isosceles trapezoid is the sum of its edge lengths:

P = 13 +8.06 +5 +8.06 = 34.12

The rectangles are 3 ft wide, so their total area is ...

A = LW = (34.12 ft)(3 ft) = 102.36 ft^2

trapezoid area

The area of a trapezoid is given by the formula ...

A = (1/2)(b1 +b2)h

A = (1/2)(13 ft +5 ft)(7 ft) = 63 ft^2

total area

As we said, the total area is the sum of the rectangle area and that of two trapezoids:

total area = rectangle area + 2 × trapezoid area

A = 102.36 ft^2 + 2 × 63 ft^2

A = 228.36 ft^2

The area of the trapezoidal prism in figure 1 is 228.36 square feet.

6 0

4 years ago