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anzhelika [568]
3 years ago
12

6. Jack is building a rectangular dog pen that he wishes to enclose. The width of the pen is 2

Mathematics
1 answer:
san4es73 [151]3 years ago
3 0

Answer:

Pretty sure the width is 3 and the length is 5.

Step-by-step explanation:

What are the multiples of 15 (3 and 5) those are the only multiples besides 1 and 15. If that makes sense.

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<img src="https://tex.z-dn.net/?f=%283%20%5Cfrac%7B2%7D%7B5%7D%20%20-%201%20%5Cfrac%7B3%7D%7B10%7D%20%29%20%5Cdiv%201%20%5Cfrac%
nata0808 [166]

Answer:

\frac{3}{2}

Step-by-step explanation:

[\frac{2}{5}-\frac{3}{10}+(3-1)]\div 1\frac{2}{5}\\\\=(\frac{4}{10}-\frac{3}{10}+2)\div\frac{5+2}{5}\\\\=(\frac{1}{10}+2)\div \frac{7}{5}\\\\=(\frac{2\cdot10+1}{10})\div \frac{7}{5}\\\\=\frac{21}{10}\div \frac{7}{5}\\\\=\frac{21}{10}\times \frac{5}{7}\\\\=\frac{21\cdot5}{10\cdot7}\\\\=\frac{3}{2}

7 0
3 years ago
Pls pls pls help meee plssss
umka21 [38]

Answer:

x = 5 or 1

Step-by-step explanation:

Square both sides to get

x^2 - 6x + 9   = 4       now subtract four from both sides

x^2 -6x+5  = 0           now factor ( or use quadratic formula)

(x-5)(x-1) = 0     so  x = 5 or 1

6 0
2 years ago
Please help with these partial fractions!!!
VARVARA [1.3K]

a. Factorize the denominator:

\dfrac{x+14}{x^2-2x-8}=\dfrac{x+14}{(x-4)(x+2)}

Then we're looking for a,b such that

\dfrac{x+14}{x^2-2x-8}=\dfrac a{x-4}+\dfrac b{x+2}

\implies x+14=a(x+2)+b(x-4)

If x=4, then 18=6a\implies a=3; if x=-2, then 12=-6b\implies b=-2. So we have

\dfrac{x+14}{x^2-2x-8}=\dfrac3{x-4}-\dfrac2{x+2}

as required.

b. Same setup as in (a):

\dfrac{-3x^2+5x+6}{x^3+x^2}=\dfrac{-3x^2+5x+6}{x^2(x+1)}

We want to find a,b,c such that

\dfrac{-3x^2+5x+6}{x^2(x+1)}=\dfrac ax+\dfrac b{x^2}+\dfrac c{x+1}

Quick aside: for the second term, since the denominator has degree 2, we should be looking for another constant b' such that the numerator of the second term is b'x+b. We always want the polynomial in the numerator to have degree 1 less than the degree of the denominator. But we would end up determining b'=0 anyway.

\implies-3x^2+5x+6=ax(x+1)+b(x+1)+cx^2

If x=0, then b=6; if x=-1, then c=-2. Expanding everything on the right then gives

-3x^2+5x+6=ax^2+ax+bx+b+cx^2=(a-2)x^2+(a+6)x+6

which tells us a-2=-3 and a+6=5; in both cases, we get a=-1. Then

\dfrac{-3x^2+5x+6}{x^2(x+1)}=-\dfrac1x+\dfrac6{x^2}-\dfrac2{x+1}

as required.

5 0
4 years ago
18. Dylan's mother tells Dylan he must spend
Klio2033 [76]

Answer:

Dylan is playing anywhere from 3.5 hours to 9.5 hours of electronic games on week days.

Step-by-step explanation:

(least estimated amount of hours played each week) 13-9.5=3.5

(highest estimated amount of hours played each week)19-9.5=9.5

If I helped you please let me know with a thank you, rating or brainly

<3Miss Hawaii<3

3 0
3 years ago
Number 1 so I can make sure I'm right
SSSSS [86.1K]

Answer:

  228.36 ft^2

Step-by-step explanation:

1. The total surface area is the area of two trapezoids and 4 rectangles. The rectangles all have the same width, so we can figure their area by finding their total length: the perimeter of the trapezoid.

<u>rectangle area</u>

The perimeter of the isosceles trapezoid is the sum of its edge lengths:

  P = 13 +8.06 +5 +8.06 = 34.12

The rectangles are 3 ft wide, so their total area is ...

  A = LW = (34.12 ft)(3 ft) = 102.36 ft^2

__

<u>trapezoid area</u>

The area of a trapezoid is given by the formula ...

  A = (1/2)(b1 +b2)h

  A = (1/2)(13 ft +5 ft)(7 ft) = 63 ft^2

__

<u>total area</u>

As we said, the total area is the sum of the rectangle area and that of two trapezoids:

  total area = rectangle area + 2 × trapezoid area

  A = 102.36 ft^2 + 2 × 63 ft^2

  A = 228.36 ft^2

The area of the trapezoidal prism in figure 1 is 228.36 square feet.

6 0
4 years ago
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