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2 years ago

If p = 2q2 - 5 and q = 10 – 3r, find a. p when r equals 2 2 b. r when p equals 67

Mathematics

1 answer:

Digiron [165]2 years ago

4 0

B.........................

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Find the radius for a circle defined by (x - 1)2 + y2 = 81.

Schach [20]

The radius is 9
The equation is
(x-h)^2 + (y-k)^2 = r^2

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2 years ago

Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En

ArbitrLikvidat [17]

Answer:

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , c) $x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$ , $y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$ .

Step-by-step explanation:

The equation of the circle is:

$x^{2} + (y-1)^{2} = 16$

After some algebraic and trigonometric handling:

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1$

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t$

Where:

$\frac{x}{4} = \cos t$

$\frac{y-1}{4} = \sin t$

Finally,

$x = 4\cdot \cos t$

$y = 1 + 4\cdot \sin t$

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

c) $x = 4\cdot \cos t''$ , $y = 1 + 4\cdot \sin t''$

Where:

$4\cdot \cos t' = 0$

$1 + 4\cdot \sin t' = 5$

The solution is $t' = \frac{\pi}{2}$

The parametric equations are:

$x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$

$y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$

7 0

3 years ago

Please answer thxxxx

Llana [10]

B. 13

12^2 + 5^2 = c^2
169 = c^2
13 = c

please mark as brainliest :D

4 0

2 years ago

Read 2 more answers

Please help me please

Brut [27]

Answer:

y=-4x+9

Step-by-step explanation:

a line parallel to another line means the two lines have the same slope

so you can already cross out the second and last equation

the y-intercept is 9 so it is positive, not a negative 9

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2 years ago

Do the indicated operation: Express your answers in the lowest terms<br><br> x/2+x/5

KonstantinChe [14]

Answer:

7x/10

Step-by-step explanation:

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2 years ago