B
C
=
16.17
(
2
d
p
)
c
m
Explanation:
In triangle ABC, side
A
C
=
15
, Angles are
∠
B
=
68
0
;
∠
C
=
24
0
and
∠
A
=
180
−
(
68
+
24
)
=
88
0
We know by sine law
A
C
sin
B
=
B
C
sin
A
or
15
sin
68
=
B
C
sin
88
or
B
C
=
15
⋅
sin
88
sin
68
=
16.17
(
2
d
p
)
c
m
Step-by-step explanation:
Answer:
Option (B). Perimeter of the quadrilateral ABCD= 14.6 units
Step-by-step explanation:
From the figure attached,
Coordinates of the vertices are A(3, 5), B(1, 3), C(3, -1), D(5, 3).
Length of AB = 
= 
= 
= 2.83 units
Length of AD = 
= 
= 2.83 units
Length of BC = 
= 
= 4.47 units
Length of DC = 
= 
= 4.47 units
Perimeter of the quadrilateral = AB + AD + DC + BC
= 2.83 + 2.83 + 4.47 + 4.47
= 14.6 units
Option (B) is the answer.
Answer:c. F(2)=g(-2)
Step-by-step explanation:
Answer:
246 in^2
Step-by-step explanation:
Given data
Length= 8 in
Width= 3 in
Height= 9 in
SA= 2( lw + wh + hl)
substitute
SA= 2(8*3+ 3*9+ 9*8)
SA= 2(24+ 27+72)
SA= 2(123)
SA= 246 in^2
Hence the SA is 246 in^2