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2 years ago

0.36x4 +0.47x3 -0.13x2-0.01x3 + 0.19x2 + x0.44x2+0.33x20.31xThe sum is

Mathematics

2 answers:

blagie [28]2 years ago

7 0

0.31x3 would be the answer

Elena-2011 [213]2 years ago

5 0

Answer:

0.31x3 is your correct answer

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If f (x)=3-2x and g (x)=1/x+5 what is the value of f/g (8)

makvit [3.9K]

F(x) = 3 - 2x
g(x) = 1/(x + 5)

(f/g)(x) = (3 - 2x) / 1/(x + 5) = (3 - 2x)(x + 5)
(f/g)(8) = (3 - 2(8))(8 + 5) = -13 x 13 = -169

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2 years ago

The population of a town increases by 4 % every year . In the last year the population of the town was 110000.

TEA [102]

Answer:

114,400 and 118,976.

Step-by-step explanation:

Let's represent this using a function. Let's let:

$P(y)$ represent the total population, and $y$ represent the total number of years since last year.

We know that the population grows by 4% every year or 0.04 every year. This is exponential growth. We can write this as:

$P(y)=110000(1.04)^y$

Note that the coefficient is 110000 because that is the year we are starting with. Also, note that it is 1.04 because we are essentially adding .04 to the original population.

Anyways, to find the present population, set y equal to 1 (because 1 year after last year is the present year)

$P(1)=110000(1.04)^1=114400$

The present population is 114,400 people.

For next year, set y equal to 2 (2 years after last year is next year)>

$P(2)=110000(1.04)^2=118976$

The population next year will be 118,976 people.

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3 years ago

Deon's gas tank is 3/10

Fittoniya [83]

Hi ANSWER. I’m am not good an English translation these真很凱越眼鍋鉤菇的菇農親還歲光銷爸匕已　鬆啊卜

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2 years ago

Sara is working on a Geometry problem in her Algebra class. The problem requires Sara to use the two quadrilaterals below to ans

zloy xaker [14]

Part A:

Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4

The perimeter of the square is given by 4(x + 4) = 4x + 16

The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12

For the perimeters to be the same

4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2

The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.

Part B:

The area of the square is given by

$Area=(x+4)^2=x^2+8x+16$

The area of the rectangle is given by 2(3x + 4) = 6x + 8

For the areas to be the same

$x^2+8x+16=6x+8 \\ \\ \Rightarrow x^2+8x-6x+16-8=0 \\ \\ \Rightarrow x^2+2x+8=0 \\ \\ \Rightarrow x= \frac{-2\pm\sqrt{2^2-4(8)}}{2} \\ \\ = \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{-28}}{2} \\ \\ = \frac{-2\pm2i\sqrt{7}}{2} =-1\pm i\sqrt{7}$

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>

7 0

3 years ago

84 is what percent of 212? round three decimal points before changing to a percent

Olegator [25]

The answer is 39.62%.

4 0

2 years ago

Read 2 more answers

0.36x4 +0.47x3 -0.13x2-0.01x3 + 0.19x2 + x0.44x2+0.33x20.31xThe sum is​

0.36x4 +0.47x3 -0.13x2-0.01x3 + 0.19x2 + x0.44x2+0.33x20.31xThe sum is