If each pack of trail mixes is targeted to weigh 9.25 oz and must be within 0.23 oz of the target in order to be accepted, then rejected masses x, are those which weighs less than 9.02 oz or greater than 9.48 oz.
Answer:
<h2>
x = 16 degrees</h2>
Step-by-step explanation:
1 and 3 are <u>vertical angles</u> so m∠1 = m∠3
(4x - 2)° = 62°
4x - 2 = 62
4x = 64
x = 16
You're answer will be C 13x2+12xy+9y2
Please, see the offered decision:
1) common equation for lines is y=kx+b. If k₁=k₂ (for line 1 and line 2) ⇒ 'line 1' || 'line 2'.
2) for line 3x+5y=6 k= -3/5. It means (according to item 1) for unknown line k is the same (-3/5).
3) using points (0;3) it is easy to find parameter b (x=0, y=3) via y=kx+b:
3=0*(-3/5)+b ⇔ b=3.
4) finaly (k=-3/5; b=3):
Answer:
4x^4 + 6x^3 + 9x^2 − 4x + 3
Step-by-step explanation:
Simplify the expression. 4x^4 + 6x^3 + 9x^2 − 4x + 3