Answer:
3p*3p*3p*3p*3p*3p
Step-by-step explanation:
Multiply exponents
3p^6
expand
3p*3p*3p*3p*3p*3p = 3p^6
Answer: 33 days.
Step-by-step explanation:
Given :- Camryn practices the trumpet every 11th day and the flute every 3rd day.
Camryn practiced both the trumpet and the flute today.
To find the number of days until Camryn practices the trumpet and flute again in the same day, we need to find the least common multiple (L.C.M.) of 11 and 3.
As they both are co-prime numbers thus its L.C.M.= 11×3=33
Therefore, Camryn practices the trumpet and flute again in the same day after 33 days.
Answer: B.x^3+4x^2-19x+14 is correct
Step-by-step explanation:
(x + 7)(x2 – 3x + 2)
Multiplying both
x^3-3x^2+2x+7x^2-21x+14
x^3+4x^2-19x+14
Answer:
the probability that a real emergency situation exists is 0.16 (16%)
Step-by-step explanation:
defining the event A= the alarm sounds ,we have
P(A)= probability that an emergency situation exists * probability that the alarm sounds given that an emergency situation exists + probability that a emergency situation does not exist * probability that the alarm sounds given that an emergency situation does not exist = 0.004* 0.95+ 0.996 * 0.02 = 0.02372
then if we use the theorem of Bayes for conditional probability and define the event E= a emergency situation exists , then
P(E/A)= P(E∩A)/P(A)= 0.004* 0.95/0.02372 =0.16 (16%)
where
P(E∩A)= probability that an emergency situation exists and the alarm sounds
P(E/A) = probability that an emergency situation exists given that the alarm has sounded
