That would be 1 and 10/11
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The point M is the midpoint of the line section PQ. Just a line fragment can have a midpoint. A line can't since it goes on uncertainly in the two bearings, thus has no midpoint. A beam can't on the grounds that it has just a single end, and henceforth no midpoint.
The Midpoint Formula works the very same way. In the event that you have to discover the point that is actually somewhere between two given focuses, simply normal the x-values and the y-values.
3x^4y^3 - 15 x^2y^2 +6xy
we can factor out 3xy
3xy(x^3y^2 -5xy+2)
we cannot factor any further
Choice A
Answer: 378.57mi²
Step-by-step explanation:
Formula = a²+2a√{(a²/4)+h²}
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The answer would be (2,3).
Try sketching it out, it helps :)