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3 years ago

What function is parallel to 3x-27=3y?

Mathematics

1 answer:

Anna [14]3 years ago

7 0

Answer:

ask google

I'm not good at maths

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Which angles are acute?

postnew [5]

Answer:

Angles DBA, GFE, and GFH (not an option) are acute.

Step-by-step explanation:

Acute means less than 90 degrees. I hope that this helps! :)

5 0

2 years ago

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Please help me answer this i will give brainliest and 5 star rating!!

VARVARA [1.3K]

Answer:

x = 77 ft

Step-by-step explanation:

55 ÷ 45 = 1.222222222

1.222222222 x 63 = 77

3 0

3 years ago

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What is the volume of a hemisphere that

ch4aika [34]

<u>Given</u>:

Given that the diameter of the hemisphere is 12.6 cm

The radius of the hemisphere is given by

$r=\frac{d}{2}=\frac{12.6}{2}=6.3$

We need to determine the volume of the hemisphere.

<u>Volume of the hemisphere:</u>

Let us determine the volume of the hemisphere.

The volume of the hemisphere can be determined using the formula,

$V=\frac{2}{3} \pi r^3$

Substituting the values, r = 6.3 and π = 3.14, we have;

$V=\frac{2}{3} (3.14)(6.3)^3$

Simplifying the values, we have;

$V=\frac{2}{3} (3.14)(250.047)$

$V=\frac{1570.29516}{3}$

Dividing, we have;

$V=523.43172$

Rounding off to the nearest tenth, we get;

$V=523.4$

Thus, the volume of the hemisphere is 523.5 cm³

6 0

3 years ago

A right circular cone is undergoing a transformation in such a way that the radius of the cone is increasing at a rate of 1/2 in

Ivenika [448]

Answer:

The volume is decreasing at the rate of 1.396 cubic inches per minute

Step-by-step explanation:

Given

Shape: Cone

$\frac{dr}{dt} =\frac{1}{2}$ --- rate of the radius

$\frac{dh}{dt} =-\frac{1}{3}$ --- rate of the height

$r = 2$

$h = \frac{1}{3}$

Required

Determine the rate of change of the cone volume

The volume of a cone is:

$V = \frac{\pi}{3}r^2h$

Differentiate with respect to time (t)

$\frac{dV}{dt} = \frac{\pi}{3}(2rh \frac{dr}{dt} + r^2 \frac{dh}{dt})$

Substitute values for the known variables

$\frac{dV}{dt} = \frac{\pi}{3}(2*2*\frac{1}{3}* \frac{1}{2} - 2^2 *\frac{1}{3})$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}* \frac{1}{2} - \frac{4}{3})$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}(\frac{1}{2} - 1))$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}*- 1)$

$\frac{dV}{dt} = -\frac{\pi}{3}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{22}{7*3}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{22}{21}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{88}{63}$

$\frac{dV}{dt} =-1.396in^3/min$

The volume is decreasing at the rate of 1.396 cubic inches per minute

3 0

3 years ago

What is 35 divided by 45

RSB [31]

0.77 is the answer to your question

3 0

3 years ago

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