You can reduce the first one by combining the ab and the ba term
Answer:
9. 6k + 5 and 2k - 1.
10. 5√2 .
Step-by-step explanation:
9. Area = 12k^2 + 4k - 5
Factoring:
12k^2 - 6k + 10k - 5
= 6k(2k - 1) + 5(2k - 1)
= (6k + 5)(2k - 1)
So the required lengths are 6k + 5 and 2k - 1.
10. The ratio of a leg to the hypotenuse is 1: √2 so if the hypotenus = 10 the length of a leg is 10 / √2
= 10 √2 / 2
= 5√2 .
The answer is 3 of each. 3X7=21; 14X3=42, and 42+21= 63.
