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Schach [20]
3 years ago
10

PLEASE HELP ASAP! PLEASE BE HONEST! ALGEBRA

Mathematics
1 answer:
Pepsi [2]3 years ago
5 0

Answer:

d. 1/3

Rise/Run

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Y=x-5; domain = {4,6,8}
Lostsunrise [7]

Answer:

Range = {-1, 1, 3}

Step-by-step explanation:

<u><em>The question asks for the range.</em></u>

The function given is

y=x-5

The domain is the set of 3 numbers:

Domain = {4,6,8}

We need to find the range.

First, the range is the set of all y-values for which the function is defined.

When we will be given the domain with a set of numbers, the range would be the numbers that we get when we evaluate the the function at those numbers.

So, we evaluate the function (y-values) at x = 4,6, and 8.

At x = 4:

y=x-5\\y=4-5\\y=-1

At x = 6:

y=x-5\\y=6-5\\y=1

At x = 8:

y=x-5\\y=8-5\\y=3

Thus, the range is:

Range = {-1, 1, 3}

7 0
3 years ago
x and y are integers between 0 and 10 that satisfy the equation shown below. x2=y⎯⎯√+3 What values for x and y satisfy the equat
8_murik_8 [283]
<span>x2=y⎯⎯√+3  
x^2 =y-1.732051</span>
7 0
3 years ago
Solve the following radical equation.<br>21*+2 - 18-3 = 18+9<br>x =​
stiks02 [169]

Answer:

x = -9, -2, and 3.

just set everything possible to 0.

since 0 = 0 it must be true.

4 0
3 years ago
HELP PLEASE <br><br>must show work <br><br>I have the answer just need to show work​
Kazeer [188]

Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) 8+6x^4

here we can see, both numbers are divisible by 2, so taking 2 common

=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)

It cannot be further simplified because both number donot have same bases.

3.4n^9 + 12 n

We can take 4n common

=4n(4n^9/4n + 12 n/4n)\\=4n(n^8 + 3)

5. -12a -3

Here -3 cam be taken common

= -3(-12a/-3 -3/-3)

= -3(4a +1)

7. 12n^5 + 16n^3

here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common

4n^3( 3n^2 + 4)

9. 5k^2 - 40k+10

Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

=5(k^2 - 8k + 2)

11.-60 + 60n^2 +50n^3

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

=10(-6 + 6n^2 +5n^3)

13. -36n^3 -12n-28

Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common

=-4(9n^3 + 3n +7)

15. 63n^3+81n+18

Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

=9(7n^3 + 9n + 2)

17. -24a^2b^2 + 36ab-60a

=6a(-4ab^2+6b-10)

3 0
3 years ago
What is the prediction of the number of coats Clothes-4-You will sell when the outside temperature is 20ºF? Round to the nearest
Nikolay [14]

Answer:

84 coats

Step-by-step explanation:

8 0
3 years ago
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