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sertanlavr [38]

2 years ago

14

The system of equations y = –2x + 1 and y = x + 5 is shown on the graph below. Which statement is true about the solution to the

system of equations?
A. The x-value is between –1 and –2, and the y-value is between 3 and 4.
B. The x-value is between 3 and 4 , and the y-value is between –1 and –2.
C. The x-value is between 1 and 2, and the y-value is between –3 and –4.
D.The x-value is between –3 and –4, and the y-value is between 1 and 2.

1 answer:

Semenov [28]2 years ago

8 0

Answer:

the answer is a

Step-by-step explanation:

y = -2x +1

y = x + 5

-2x+1=x+5

-3x = 4

x= -4/3

y = -1 1/3 + 5= 3 2/3

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Horatio is solving the equation -3/4+2/5x=7/20x-1/2. Which equations represent possible ways to begin solving for x? Check all t

trapecia [35]

Answer:

2/5x=7/20x+1/4
-3/4=-1/20x-1/2
-3/4+1/20x=-1/2

Step-by-step explanation:

If you add 3/4 to both sides of the equation, you get ...

... 2/5x = 7/20x + 1/4 . . . . first choice

If you subtract 2/5x from both sides of the equation, you get ...

... -3/4 = -1/20x -1/2 . . . . third choice

If you subtract 7/20x from both sides of the equation, you get ...

... -3/4 +1/20x = -1/2 . . . . last choice

Choices 2 and 4 are erroneous versions of choices 1 and 3, so do not apply.

4 0

2 years ago

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How to to this problem

bulgar [2K]

Can you post a clearer picture?

7 0

2 years ago

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2). What is the area of the triangle? a 18 square units b 9 square unit

natka813 [3]

Answer:

Option C. 6 square units

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.

Let

a,b,c be the lengths of the sides of a triangle.

The area is given by:

$A=\sqrt{p(p-a)(p-b)(p-c)}$

where

p is half the perimeter

p= $\frac{a+b+c}{2}$

we have

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$d=\sqrt{(-3-1)^{2}+(-2+2)^{2}}$

$d=\sqrt{(-4)^{2}+(0)^{2}}$

$dAB=4\ units$

step 2

Find the distance BC

$d=\sqrt{(-2+3)^{2}+(1+2)^{2}}$

$d=\sqrt{(1)^{2}+(3)^{2}}$

$dBC=\sqrt{10}\ units$

step 3

Find the distance AC

$d=\sqrt{(-2-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-3)^{2}+(3)^{2}}$

$dBC=\sqrt{18}\ units$

step 4

$a=AB=4\ units$

$b=BC=\sqrt{10}\ units$

$c=AC=\sqrt{18}\ units$

Find the half perimeter p

p= $\frac{4+\sqrt{10}+\sqrt{18}}{2}=5.70\ units$

Find the area

$A=\sqrt{5.7(5.7-4)(5.7-3.16)(5.7-4.24)}$

$A=\sqrt{5.7(1.7)(2.54)(1.46)}$

$A=\sqrt{35.93}$

$A=6\ units^{2}$

7 0

2 years ago

What is 2 3/10 as a decimal

Lesechka [4]

2.3 will be your answer

2 for the 2 (whole)
.3 is 3/10

if it was 3/100, it will be .03

hope this helps

3 0

3 years ago

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Urgent help needed...............

andreyandreev [35.5K]

Answer:

Option b is correct

$\{x | x \neq \pm 7, x\neq 0\}$ .

Step-by-step explanation:

Domain is the set of all possible values of x where function is defined.

Given the function:

$h(x) = \frac{9x}{x(x^2-49)}$

To find the domain of the given function:

Exclude the values of x, for which function is not defined

Set denominator = 0

$x(x^2-49) = 0$

By zero product property;

$x = 0$ and $x^2-49= 0$

⇒x = 0 and $x^2 =49$

⇒x = 0 and $x = \pm 7$

Therefore, the domain of the given function is:

$\{x | x \neq \pm 7, x\neq 0\}$

7 0

3 years ago

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