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notsponge [240]
3 years ago
6

Please help How many moles are there in 7.57 x 10^30 molecules of CO2?

Chemistry
1 answer:
Oxana [17]3 years ago
3 0

Answer:

The answer is

<h2>12,574,750.83 moles</h2>

Explanation:

In order to find the moles of CO2 we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 7.57 × 10^30 molecules of CO2

We have

n =  \frac{7.57 \times  {10}^{30} }{6.02 \times  {10}^{23} }  \\  = 12574750.83056...

We have the final answer as

<h3>12,574,750.83 moles</h3>

Hope this helps you

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Answer:

H₃O⁺(aq) + CO₃²⁻(aq) ⟶ HCO₃⁻(aq) + H₂O(ℓ)

Explanation:

There are three steps you must follow to get the answer.

You must write the:

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  2. Ionic equation
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1. Molecular equation

HNO₃(aq) + Li₂CO₃(aq) ⟶ LiNO₃(aq) + LiHCO₃(aq)

2. Ionic equation

You write the molecular formulas for the weak electrolytes, and you write the ionic substances as ions.

H₃O⁺(aq) + NO₃⁻(aq) + 2Li⁺(aq) + CO₃²⁻(aq) ⟶ Li⁺(aq)(s) + NO₃⁻(aq) + Li⁺(aq) + HCO₃⁻(aq) + H₂O(ℓ)

3. Net ionic equation

To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.

H₃O⁺(aq) + <u>NO₃⁻(aq)</u> + <u>2Li⁺(aq)</u> + CO₃²⁻(aq) ⟶ <u>Li⁺(aq)</u> + <u>NO₃⁻(aq</u>) +<u> Li⁺(aq)</u> + HCO₃⁻(aq) + H₂O(ℓ)

The net ionic equation is

H₃O⁺(aq) + CO₃²⁻(aq) ⟶ HCO₃⁻(aq) + H₂O(ℓ)

8 0
3 years ago
Which is a saturated solution?
ser-zykov [4K]

Answer:

C)52g KCl in 100g water at 80°C

Explanation:

A saturated solution is one that contains as much solute as it can dissolve in the presence of excess solute at that particular temperature.

A solutibility curve is a graph that shows the variability with temperature of the solubility of a solute in a given solvent. A solutibility curve can provide information of whether a solution formed frommthe solute and solvent are saturated or not at a given temperature.

From the solubility curve in the attachment below:

A) A saturated solution of NH₄Cl will contain about 52 g solute per 100 g sat 50 °C. Thus, a solution of 40 g NH₄Cl in 100 g water at 50 °C is an unsaturated solution.

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C) A saturated solution of KCl at 80 °C will contain about 52 g of solute in 100 g of water. Thus, a solution of 52g KCl in 100g water at 80°C is a saturated solution.

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7 0
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5 0
4 years ago
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Answer:

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8 0
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