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notsponge [240]
3 years ago
6

Please help How many moles are there in 7.57 x 10^30 molecules of CO2?

Chemistry
1 answer:
Oxana [17]3 years ago
3 0

Answer:

The answer is

<h2>12,574,750.83 moles</h2>

Explanation:

In order to find the moles of CO2 we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 7.57 × 10^30 molecules of CO2

We have

n =  \frac{7.57 \times  {10}^{30} }{6.02 \times  {10}^{23} }  \\  = 12574750.83056...

We have the final answer as

<h3>12,574,750.83 moles</h3>

Hope this helps you

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[20pts] I want to start counterfeiting American pennies. Each penny weighs 2.56g and I want $200.00 of pennies for my scheme. Se
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Answer:

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Explanation:

The <em>dimensional analysis</em> helps you by focusing your attention into the units: you must set up the equation starting with the available units and add the factors with the units such that the cancelation of numerators and denominators ends up with the desired units: grams of aluminium in this case.

In this case, you start with a mass of 2.56 grams per penny, which is 2.56g/penny, whose value is $200.00 and want to end with the grams of

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Then, you must use the mole ratios derived from the chemical equation in a way that the units lead from grams of copper to grams of aluminium.

The equation is:

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From which, the mole ratio between copper and aluminium is:

           2molAl(s):3molCu(s)\\\\\dfrac{2molAl}{3molCu},or\\\\\\\dfrac{3molCu}{2molAl}

You must also use the atomic masses of Cu and Al which are 63.5g/mol and 27g/mol respectively.

The equation is:

     

          \$200.00\times 100\dfrac{penny}{\$}\times \dfrac{2.56g}{penny}\times \dfrac{1molCu}{63.5gCu}\times \dfrac{2molAl}{3molCu}\times \dfrac{27gAl}{1molAl}

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<h2>Answer:</h2>

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