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olchik [2.2K]
2 years ago
14

Using the formula M1V1 = M2V2 , how many milliliters of a 2.50 M hydrochloric acid solution is required to make 100.0 mL of a 0.

750 M solution?
30mL
1.88
300mL
333mL
Chemistry
2 answers:
olga nikolaevna [1]2 years ago
8 0

30ml of a 2.50 M hydrochloric acid solution is required to make 100.0 mL of a 0.750 M solution.

<h3>What is HCl?</h3>

HCl is an acid which is made up of hydrogen and chlorine gas.

By the formula of dilution

M1V1 = M2V2

where V1 = 2.50 m

M2 = 100.0

V2 = 0.750 m

M1 × 2.50 m = 100.0 × 0.750 m

M1 = 30 ml

Thus, the M1 is 30 ml option a is correct.

Learn more about HCl

brainly.com/question/3637432

Alex2 years ago
6 0

Answer:

<u>30mL</u> is required

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Thickness of the oil drop is 1 molecule thick.So, let the thickness of the drop or diameter of the molecule be x.

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6 0
2 years ago
How many L are in 1,500cm^3<br><img src="https://tex.z-dn.net/?f=1500%7Bcm%7D%5E%7B3%7D%20%3D%20%5C%3A%20...%20%20%5C%3A%20liter
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You need to make 10.0 L of 1.2 M KNO3. What molar ( concentration) would the potassium nitrate solution need to be if you were t
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Answer:

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By definition Molarity = moles solute/volume of solution in Liters

=> moles solute = Molarity x Volume (L)

Apply moles before dilution = moles after dilution ...

=> (Molarity X Volume)before dilution = (Molarity X Volume)after dilution

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The heat of vaporization of 1-pentanol is 55.5 kJ/mol, and its entropy of vaporization is 148 J/K.mol. What is the approximate b
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Answer:

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Explanation:

Hello,

In this case, since the entropy of vaporization is computed in terms of the heat of vaporization and the temperature as:

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We can solve for the temperature as follows:

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Hence, answer is approximately 100 °C.

Best regards.

6 0
2 years ago
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