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11 months ago

Find the appropriate number of significant figures

Chemistry

1 answer:

xz_007 [3.2K]11 months ago

8 0

Answer:

Non-zero digits are always significant

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The amount of heat involved in the synthesis of 1 mole of a compound from its elements, with all substances in their standard st

Pachacha [2.7K]

Answer:

Explanation:

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3 years ago

Read 2 more answers

What charge would an arsenic, As, ion have? Explain.

leva [86]

Answer:

Arsenic (As) anion has -‐3 charge, but also forms cations with +3 or +5 charge.

Explanation:

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2 years ago

Which electron transition represents a gain of energy?

xz_007 [3.2K]

The correct answer is (A) from 2nd to 3rd shell.

The explanation :

when a gain of energy is the shift of the electrons from a shell of low energy to the shell of high energy

and we have here 2nd shell is the shell of low energy, and 3rd shell is the shell of high energy.

∴ (A) from 2nd to 3rd shell is the correct answer.

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3 years ago

Which is the larger atom As or P

sashaice [31]

Answer:

I think that As is larger

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3 years ago

HELP. I DONT KNOW WHAT TO DO. Barium sulfate, BaSO4, is made by the following reaction.

Ghella [55]

Answer:

$\boxed{\text{66.95 g BaSO$_{4}$}}$

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.

M_r: 261.34 233.39

Ba(NO₃)₂ + Na₂SO₄ ⟶ BaSO₄ + 2NaNO₃

m/g: 75.00

1. Moles of Ba(NO₃)₂

$\text{Moles of Ba(NO$_{3})_{2}$} = \text{75.00 g} \times \dfrac{\text{1 mol}}{\text{261.34 g}} = \text{0.286 98 mol}$

2. Moles of BaSO₄

The molar ratio is (1 mol BaSO₄/1 mol Ba(NO₃)₂

$\text{Moles of BaSO$_{4}$}= \text{0.286 98 mol Ba(NO$_{3})_{2}$ } \times \dfrac{\text{1 mol BaSO$_{4}$}}{\text{1 mol Ba(NO$_{3})_{2}$}} = \text{0.286 98 mol BaSO$_{4}$}$

3. Mass of BaSO₄

$\text{Mass of BaSO$_{4}$} = \text{0.286 98 mol BaSO$_{4}$} \times \dfrac{\text{233.39 g BaSO$_{4}$}}{\text{1 mol BaSO$_{4}$}} = \textbf{66.98 g BaSO$_{4}$}\\\\\text{The theoretical yield of barium sulfate is } \boxed{\textbf{66.98 g BaSO$_{4}$}}$

8 0

3 years ago