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swat32
3 years ago
6

What happens to the rate of dissolution as the temperature is increased in a gas solution?

Chemistry
1 answer:
Nina [5.8K]3 years ago
8 0

Answer:

The rate decreases

Explanation:

When we dissolve a gas in a water, the process is exothermic. This implies that heat is evolved upon dissolution of a gas in water.

Recall from Le Chateliers principle that for exothermic reactions, an increase in temperature favours the reverse reaction. The implication of these is that when the temperature of the gas is increased, less gas will dissolve in water.

Hence increase in temperature decreases the rate of solubility of a gas in water.

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When is friction advantageous and when is it not advantageous? Explain.
Novosadov [1.4K]

Answer:

here

Explanation:

FRICTION ADVANTAGES:

a) the soles of are shoes are designed in a way that they create friction and prevent us from slipping and falling.

b) We are capable of writing with a pen due to the friction between the pen and the paper.

FRICTION DISADVANTAGES:

b) Forest fires are caused due to the friction between the trees branches

( please vote me for brainliest )

5 0
3 years ago
(a.) a 0.7549g sample of the compound burns in o2(g) to produce 1.9061g of co2(g) and 0.3370g of h2o(g).
Natali [406]

The individual mass of C, H and O in given sample are 0.5196 g, 0.0374 g and 0.1979 g respectively.

Moles of CO2 formed can be calculated as

= Mass of CO2 / Molar mass of CO2

= 1.9061 / 44 = 0.0433 moles

<h3>Calculation of no. of moles of carbon</h3>

Now, moles of C which is present in one mole of CO2 = 1 mole

Moles of C in 0.0433 moles of CO2 = 0.0433 moles

As we know that, molar mass of C = 12 g / mol

Mass of C in 0.7549 g of given sample can be calculated as

= 0.0433 × 12 =0.5196 g

Mass of H2O formed = 0.3370 g

Similarly, Molar Mass of H2O = 18 g / mol

Moles of H2O = 0.3370 / 18 = 0.0187 moles

Moles of H present in 1 mole of H2O = 2 moles

Moles of H present in 0.0187 mole of H2O = 2 × 0.0187 = 0.0374 moles

Molar mass of H = 1 g / mol

Mass of H contained in 0.7549 g of sample = 1 × 0.0374= 0.0374 g

Mass of O in 0.7549 g sample can be calculated as

= 0.7549 – [(Mass of C ) + (Mass of H) ]

= 0.7549 – [ (0.5196) + (0.0374) ]

= 0.1979 g

Thus, we calculated that the individual mass of C, H and O in given sample are 0.5196 g, 0.0374 g and 0.1979 g respectively.

learn more about Moles:

brainly.com/question/26416088

#SPJ4

DISCLAIMER: THE above question is incomplete. Complete question is given below:

A 0.7549g sample of the compound burns in o2(g) to produce 1.9061g of co2(g) and 0.3370g of h2o(g). Calculate the individual mass of C, H and O in the given sample.

4 0
1 year ago
What is crystal field splitting?
kvv77 [185]

Answer:

Crystal field splitting is the difference in energy between d orbitals of ligands. Crystal field splitting number is denoted by the capital Greek letter Δ. Crystal field splitting explains the difference in color between two similar metal-ligand complexes.

4 0
3 years ago
Which type of stoichiometry problems does not require the use of molar mass?
Arlecino [84]

Answer:

Explanation:

It is volume-volume problems that does not require the use of molar mass.

7 0
3 years ago
I need help on #'s 4 and 5
kompoz [17]
The answer for four is frequency.
3 0
3 years ago
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