44% 11/25 are both the answers
Answer:
Alguien me ayuda es para mañana
Given:
Zero: 2, multiplicity: 3
Zero: 0, multiplicity: 2
Degree: 5
Leading coefficient = 1
To find:
The polynomial function.
Solution:
The general form of a polynomial is
where, a is a constant, 
are zeroes with multiplicity 
.
Using the given information and the general form of a polynomial, we get
Leading coefficient is 1, so the value of a is also 1.
Therefore, the required polynomial is .
The triangle has sides a,b,c such that
a = 2*sqrt(5), b = sqrt(5), and c = 2*sqrt(10)
Square each value
a = 2*sqrt(5)
a^2 = (2*sqrt(5))^2
a^2 = 2^2(sqrt(5))^2
a^2 = 4*5
a^2 = 20
b^2 = 20 for similar reasons as side 'a'
c = 2*sqrt(10)
c^2 = (2*sqrt(10))^2
c^2 = 2^2*(sqrt(10))^2
c^2 = 4*10
c^2 = 40
------------------------------------
Using the pythagorean theorem, we see that
a^2 + b^2 = c^2
20 + 20 = 40
40 = 40
So the initial equation a^2 + b^2 = c^2 is true making the triangle with sides a,b,c defined above to be a right triangle
