After 24 hours, 35.4% of the initial dosage remains on the body.
<h3>What percentage of the last dosage remains?</h3>
The exponential decay is written as:

Where A is the initial value, in this case 2.8mg.
k is the constant of decay, given by the logarithm of 2 over the half life, in this case, is:

Replacing all that in the above formula, and evaluating in x = 24 hours we get:

The percentage of the initial dosage that remains is:

If you want to learn more about exponential decays:
brainly.com/question/11464095
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If you're looking for equivalents to 3^x, choices
... D. (15^x)/(5^x)
... E. (15/5)^x
... F. 3×3^(x-1)
are the only ones that qualify.
Answer:
m = −1−4 = 14.
y − y1 = (1/4)(x − x1)
y − 2 = (1/4)(x − 7)
y − 2 = x/4 − 7/4
Step-by-step explanation:
google
Answer:
its answer C. y=-8
Step-by-step explanation:
y=-8 passes through (-2, -8) and is parallel to y=3 because they're both horizontal
<span>The data value must be less than the mean.</span>