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Jet001 [13]
3 years ago
10

Find the area of the figure. 36 cm 28.8 cm 21.6 cm

Mathematics
2 answers:
svp [43]3 years ago
5 0
86.4 is the answer to this problem .
dem82 [27]3 years ago
3 0

Answer:

86.4

Step-by-step explanation:

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Check the picture below.

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\bf tan(\theta )=\cfrac{y}{x}\implies tan(\theta )=\cfrac{y}{15}\implies tan(\theta )=\cfrac{1}{15}\cdot y
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\stackrel{chain~rule}{sec^2(\theta )\cfrac{d\theta }{dt}}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}\implies \cfrac{1}{cos^2(\theta )}\cdot\cfrac{d\theta }{dt}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}
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\boxed{\cfrac{d\theta }{dt}=\cfrac{cos^2(\theta )\frac{dy}{dt}}{15}}\\\\
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\bf cos(\theta )=\cfrac{adjacent}{hypotenuse}\implies cos(\theta )=\cfrac{15}{15\sqrt{5}}\implies cos(\theta )=\cfrac{1}{\sqrt{5}}\\\\
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\cfrac{d\theta }{dt}=\cfrac{\left( \frac{1}{\sqrt{5}} \right)^2\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{1}{5}\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{11}{5}}{15}\implies \cfrac{d\theta }{dt}=\cfrac{11}{5}\cdot \cfrac{1}{15}
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\cfrac{d\theta }{dt}=\cfrac{11}{75}

8 0
3 years ago
Can someone please help me
MaRussiya [10]

Answer:

The answer is B)

Step-by-step explanation:

Use the Distance Formula

d = sqr(1 + 3)^2 + (0 - 4)^2

d = sqrt(32)

d = 4*sqrt(2)


7 0
3 years ago
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