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2 years ago

12

NO LINKS I WILL REPORT!!! But help PLSS It's possible to build a triangle with side lengths of 5, 7, and 11.

2 answers:

strojnjashka [21]2 years ago

8 0

Answer:

yes it is possible

I hope it's helps you

Misha Larkins [42]2 years ago

7 0

Answer:

The answer is False !!!!!!!!

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$\frac{1}{3} (9x-6)2x=3 \\ \\ \frac{(9x-6) \times 2x}{3} = 3 \\ \\ \frac{3(3x - 2) \times 2x}{3} = 3 \\ \\ \frac{6x (3x-2)}{3} = 3 \\ \\ 2x(3x-2) = 3 \\ \\ 6x^2 - 4x = 3 \\ \\ 6x^2 - 4x - 3 = 0 \\ \\ x = \frac{4+2 \sqrt{22} }{12} , \frac{2- \sqrt{22} }{12} \\ \\ x = \frac{2+ \sqrt{22} }{6} , \frac{2- \sqrt{22} }{6}$

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2 years ago

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Step-by-step explanation:

What is half of 1/3? The options are: 2/3, 2 1/2, 4/9, and 2 and 2 halves

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Step-by-step explanation:

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3 years ago

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Factorise x^2+6x-7 ?? Help please

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$x^2+6x-7=\\
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2 years ago