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Makovka662 [10]
3 years ago
7

If A and B are independent events and P(A) and P(B) are both greater than 1/2

Mathematics
1 answer:
elixir [45]3 years ago
7 0

Answer:

P(A and B) is greater than 1 is never happened ⇒ C

Step-by-step explanation:

Two events are independent if the result of the second event is not  affected by the result of the first event

If A and B are independent events, the probability of both events  is the product of the probabilities of the both events  P (A and B) = P(A) · P(B)

∵ The probability of any event is less than 1

∵ P(A) < 1

∵ P(A) > \frac{1}{2}

- That means P(A) is greater than half and less than 1

∴ \frac{1}{2} < P(A) < 1

∵ P(B) < 1

∵ P(B) > \frac{1}{2}

- That means P(B) is greater than half and less than 1

∴ \frac{1}{2} < P(B) < 1

∵ P(A and B) = P(A) . P(B)

- Remember the product of any fractions less than 1 is less than 1

∴ \frac{1}{4} < P(A) . P(B) < 1

- That means any expression equals to P(A) . P(B) must be greater

   than \frac{1}{4} and less than 1

∴ \frac{1}{4} < P(A and B) < 1

∴ P(A and B) is greater than 1 is never happened

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Step-by-step explanation:

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3 years ago
Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams
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Answer:

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Step-by-step explanation:

We solve using z score formula

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Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.

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z = 1150 - 1387/192

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Probability value from Z-Table:

P(x = 1150) = 0.10853

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z = 1308 - 1387/192

= -0.41146

Probability value from Z-Table:

P(x = 1308) = 0.34037

Proportion of broilers weigh between 1150 and 1308 grams is:

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(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

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= 0.64063

Probabilty value from Z-Table:

P(x<1510) = 0.73912

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No it is not unusual for a broiler to weigh more than 1610 grams

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