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2 years ago

8

Tom deposits $1000 into a savings account. That earns 5% simple interest. He has this account for 7 years. How much does it cont

ain now?

1 answer:

Arada [10]2 years ago

3 0

Answer:

$1350

Step-by-step explanation:

5% of 1000 is 50

50x7 is 350

1000+350=1350

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Can someone please help me with the second question….will give brainliest :(

den301095 [7]

Answer:

its 3.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The wildflowers at a national park have been decreasing in numbers. There were 1200 wildflowers in the first year that the park

bonufazy [111]

Year New flowers

1 1200

2 300

3 75

There were 1200 wildflowers in the first year that the park started tracking them. Since then, there have been one fourth as many new flowers each year

Initially there are 1200 flowers and start decreasing by $\frac{1}{4}$

So first term is 1200 and common ratio is $\frac{1}{4}$ .

Its a geometric sequence so summation becomes

i =1∑ ∞ 1200( $\frac{1}{4})^{i-1}$

Now we find the sum

We use sum formula

$Sum = \frac{a}{1-r}$

Where a is the first term , a= 1200

r is the common ratio , r= 1/4

$Sum = \frac{1200}{1-(\frac{1}{4})}$

$Sum = \frac{1200}{\frac{3}{4}}$

Sum = 1600 wildflowers

4 0

3 years ago

if a right triangle has one side measuring 3√2 and another side measuring 2√3, what is the length of the hypotenuse?

lina2011 [118]

Answer:

<h2> $\sqrt{30}$ </h2>

Step-by-step explanation:

Given,

Perpendicular ( p ) = 3√2

Base ( b ) = 2√3

Hypotenuse ( h ) = ?

Now, let's find the length of the hypotenuse:

Using Pythagoras theorem:

${h}^{2} = {p}^{2} + {b}^{2}$

plug the values

${h}^{2} = {(3 \sqrt{2} )}^{2} + {(2 \sqrt{3} )}^{2}$

To raise a product to a power, raise each factor to that power

${h}^{2} = 9 \times 2 + 4 \times 3$

Multiply the numbers

${h}^{2} = 18 + 12$

Add the numbers

${h }^{2} = 30$

Take the square root of both sides of the equation

$h = \sqrt{30}$

Hope this helps...

Best regards!!

6 0

3 years ago

Read 2 more answers

If X is a random variable denoting number of defective items, which discrete probability distribution is appropriate

Lesechka [4]

Considering that for each item, there are only two possible outcomes, and the probability of an item being defective is independent of any other item, the binomial distribution is appropriate.

<h3>What is the binomial probability distribution?</h3>

It is the probability of <u>exactly x successes on n repeated trials, with p probability</u> of a success on each trial.

More can be learned about the binomial distribution at brainly.com/question/24863377

6 0

1 year ago

I don't know how to do this but I know you have to find the growth or decay

xenn [34]

Answer:

$\boxed{y=5(1.05)^t\to\:5\% \:rate \:of \:growth}$

$\boxed{f(t)=50(.95)^t\to\:5\% \:rate \:of \:decay}$

$\boxed{g(t)=50(1.5)^t\to\:50\% \:rate \:of \:growth}$

$\boxed{y=5(.5)^t\to\:50\% \:rate \:of \:decay}$

Step-by-step explanation:

We can rewrite the given functions in the form $f(x)=a(100\%+r\%)^x$ to determine the rate of growth or $f(x)=a(100\%-r\%)^x$ to determine the rate of decay

$y=5(1.05)^t=5(100\%+5\%)^t\to\:5\% \:rate \:of \:growth$

$f(t)=50(.95)^t=50(100\%-5\%)^t\to\:5\% \:rate \:of \:decay$

$g(t)=50(1.5)^t=50(100\%+50\%)^t\to\:50\% \:rate \:of \:growth$

$y=5(.5)^t=5(100\%-50\%)^t\to\:50\% \:rate \:of \:decay$

4 0

3 years ago