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2 years ago

Solve 3 3/5 x (-8 1/3)

Mathematics

2 answers:

guajiro [1.7K]2 years ago

8 0

Answer:

The answer to this problem is -24/5.

Vitek1552 [10]2 years ago

5 0

The answer is -30x
Hope that helps!

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The company, hewerrtt, would like to make letter codes using all of the letters in the word hewerrtt. how many codes can be made

shtirl [24]

If the company, hewerrtt, would like to make letter codes using all of the letters in the word hewerrtt, they would be able to make five codes. Altogether, there are eight letters in the word, but there are duplicates of the letter e, the letter r, and the letter t, so that takes out three possibilities. Three subtracted from eight is equal to five, therefore the company can make five codes using the company name.

8 0

2 years ago

Read 2 more answers

What is the conjugate? square root of 8 - square root of 9

elixir [45]

Answer:

-0.17157287525

Step-by-step explanation:

1. The square root of 8 will never be a whole number so it is 2.82842712475

2. Square root of 9 is 3.

3. You can already realize that the answer will not be whole or positive

4. Subtract in order.

5. The answer is -0.17157287525

4 0

2 years ago

Solve for n. n^2–15n–16=0

Fofino [41]

N = {15 +- root of ( 225 + 64) } / 2
= {15 +- root of 289 } / 24
= 15 + 17 } / 2 or { 15 -17 } /2
= 16 or -1

5 0

2 years ago

There are 20 chocolate candies in a bag.

Eduardwww [97]

Answer:

Step-by-step explanation:

20/20 X 100 = 100%

have a good day

3 0

2 years ago

a collection of dimes and quarters is worth $19.85. There are 128 coins in all. How many of each type of coin are in the collect

PolarNik [594]

Number of dimes were 81 and number of quarters were 47

Solution:

Let "d" be the number of dimes

Let "q" be the number of quarters

We know that,

value of 1 dime = $ 0.10

value of 1 quarter = $ 0.25

Given that There are 128 coins in all

number of dimes + number of quarters = 128

d + q = 128 ------ eqn 1

Also given that collection of dimes and quarters is worth $19.85

number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 19.85

$d \times 0.10 + q \times 0.25 = 19.85$

0.1d + 0.25q = 19.85 -------- eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

d = 128 - q -------- eqn 3

Substitute eqn 3 in eqn 2

0.1(128 - q) + 0.25q = 19.85

12.8 - 0.1q + 0.25q = 19.85

12.8 + 0.15q = 19.85

0.15q = 7.05

Therefore from eqn 3,

d = 128 - q

d = 128 - 47

Thus number of dimes were 81 and number of quarters were 47

4 0

2 years ago