Answer:
The correct answer is first option 60%
Step-by-step explanation:
The radius of a circle is inscribed in an equilateral triangle with side a = a/2√3
<u>To find the area of equilateral triangle</u>
Here side be 'a'
Area of equilateral = √3a²/4
<u>To find the area of circle</u>
Here radius = a/2√3
Area = πr²
= π(a/2√3)
= 3.14a²/12
<u>To find the probability</u>
probability = area of circle/area of triangle
= 3.14a²/12/ √3a²/4
= 3.14/3√3
= 0.6043 ≈ 60.43 % 60 %
The correct answer is first option 60%
Answer:
1. 
2. not completely sure but i think its 
3.x
=
2
i
√
5
,
−
2
i
√
5
4.x
=
−
9
±
√
73
/2
5. Im not sure...
☀️☀️☀️☀️☀️☀️Hope This Helps☀️☀️☀️☀️☀️☀️
We have been given that an employee shreds 341 pages in 11 minutes of work.
First of all we will divide 341 by 11 to find number of pages shred by employee in one minute.

Now let us multiply 31 by 20 to find number of pages shred by employee in 20 minutes.

Therefore, employee will shred 620 pages in 20 minutes.
This question has extraneous info to trick you.
f(x) = g(x)h(x) ⇒ f'(x) = g'(x)h'(x) . Letting x = 10, we get f'(10) = g'(10)h'(10). then just plug in the values provided. g(10) and h(10) are there to throw you off, just use g'(10) and h'(10).
So f'(10), pronounced "eff prime of ten", = 0 * 35 = 0.
If the question were asking for f(10) instead of f'(10) then you would use g(10) and h(10), ⇒-4*560=90.
Answer:
1195.22N.
Step-by-step explanation:
Mass: m =82.6 kg
Velocity: v= 16.4m/sec.
Distance: d = 9.29 metres.
Acceleration = (v²/2d) = (16.4²/18.58) = 14.47m/sec².
Force = (mass x acceleration) = (82.6 x 14.47) = 1195.22N.