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3 years ago

10

Solve

\frac{4}{6v}" alt="\frac{6}{4} +\frac{4}{6v}" align="absmiddle" class="latex-formula">

1 answer:

Arada [10]3 years ago

3 0

Answer:

(9v + 4) / 6v.

Step-by-step explanation:

6/4 + 4/6v

The LCD of 4 and 6v is 12v.

6/4 + 4/6v

= (6* 3v + 8) / 12v

= (18v + 8)/12v

= 2(9v + 4) / 12v

= (9v + 4) / 6v.

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Umnica [9.8K]

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When measuring and recording vital signs, healthcare professionals sometimes have to convert units of measurement, especially wh

nataly862011 [7]

Answer:

116°F = 46.67 °C and 6 Pounds = 2721.55 grams

Step-by-step explanation:

The information given in the question is 1°F = -17.22°C

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1) We know (°F-32)×5/9 =°C

So by putting the value of °F as 116 ⇒ (116-32)×5÷9 = °C

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3 years ago

If we list all the natural numbers below 20 that are multiples of 7 or 11, we get 7, 11 and 14. The sum of these multiples is 32

velikii [3]

Number of multiples of 7 up to 1337: $\left\lfloor\dfrac{1337}7\right\rfloor=191$
Number of multiples of 11 up to 1337: $\left\lfloor\dfrac{1337}{11}\right\rfloor=121$
Number of multiples of 77 up to 1337: $\left\lfloor\dfrac{1337}{77}\right\rfloor=17$

This means there are $191+121-17=295$ distinct multiples of 7 *or* 11 up to 1337.

The sum of these multiples is

$\displaystyle\sum_{k=1}^{191}7k+\sum_{k=1}^{121}11k-\sum_{k=1}^{17}77k$

which can be computed using the well-known formula,

$\displaystyle\sum_{k=1}^nk=\dfrac{n(n+1)}2$

So you have

$\displaystyle\sum_{k=1}^{191}7k+\sum_{k=1}^{121}11k-\sum_{k=1}^{17}77k=7\dfrac{191\times192}2+11\dfrac{121\times122}2-77\dfrac{17\times18}2=197762$

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3 years ago

What are the domain and range of each relation?

torisob [31]

Order pairs given coordinates on the graph: {(−3, 1), (−3, -4), (−1, 1), (1, -1), (4,4)}.

We need to find the domain and range.

<em>Domain of the order pairs are x values of each coordinate and range is the y values of each given coordinate.</em>

Each first value of order pair are the x values and each second value of each order pair are the y values.

In the given coordinates on the graph (−3, 1), (−3, -4), (−1, 1), (1, -1), (4,4), we can see first values are { -3,-1, 1, 4}

and we can see second values are { -4, -1, 1, 4}.

<h3>Therefore, Domain : { -3,-1, 1, 4} and </h3><h3>Range : { -4, -1, 1, 4}</h3>

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4 years ago