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3 years ago

If the measure of ABC is 68°, what is the measure of AB? B 68 А c

Mathematics

1 answer:

Radda [10]3 years ago

5 0

Answer:

A: 24

B: 33

Step-by-step explanation:

A: 24

B: 33

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I have 2 questions. Please help me with them. Thank you.

zavuch27 [327]

(x+8)^(2) + (y+9)^(2) = 169
(x+8)^(2) + (y+9)^(2) = 13^2

h = -8
k = -9
r = 13

answer
A. center (-8,-9)
radius = 13

--------------

(x-7)^2 + y^2 = 225
(x-7)^2 + y^2 = 15^2

h = 7
k = 0
r = 15

answer
B. center (7,0)
radius = 15

6 0

3 years ago

Negative two and three sevenths times 0.01

kirill [66]

Answer:

-0.02428571428

3 0

3 years ago

The point (0, 0) is a solution to which of these inequalities? A. y – 4 < 3x – 1 B. y – 1 < 3x – 4 C. y + 4 < 3x – 1 D.

miskamm [114]

Answer:

Step-by-step explanation:

Replace the point (0,0) in each inequality

A. y - 4 < 3x - 1

B. y - 1 < 3x - 4

C. y + 4 < 3x - 1

D. y + 4 < 3x + 1

A. 0 - 4 < 3(0) - 1

- 4 < - 1

True

B. 0 - 1 < 3(0) - 4

- 1 < - 4

False

C. y + 4 < 3x - 1

0 + 4 < 3(0) - 1

4 < - 1

False

D. y + 4 < 3x + 1

0 + 4 < 3(0) + 1

4 < 1

False

5 0

3 years ago

Let the region R be the area enclosed by the function f(x)=ln(x) and g(x)= 1/2x-2. Find the volume of the solid generated when t

Neporo4naja [7]

Answer:

$V=61.66$

Step-by-step explanation:

This problem can be solved by using the expression for the Volume of a solid with the washer method

$V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx$

where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).

Before we have to compute the limits of the integral. We can do that by taking f=g, that is

$f(x)=g(x)\\ln(x)=\frac{1}{2}x-2$

there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)

x1=0.14

x2=8.21

and because the revolution is around y=-5 we have

$R=ln(x)-(-5)\\r=\frac{1}{2}x-2-(-5)\\$

and by replacing in the integral we have

$V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\$

$V=\pi [28x+\frac{1}{x}+xln^2x-12xlnx-6lnx]$

and by evaluating in the limits we have

$V=61.66$

Hope this helps

regards

3 0

3 years ago

Literally anyone HELP

barxatty [35]

Answer:

the answer is the last one, you solve this by comparing the lines from each shape. these shapes are congruent, meaning they're the same, so the like AB on the first shape and EF on the second are the same, and so on if that makes any sense. surely someone else could do a better explanation than me tho

6 0

3 years ago