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3 years ago

Determine the molecular weight of Ca3(PO4)2. 278.18 g 279.21 g 310.18 g 430.42 g

Chemistry

2 answers:

sergiy2304 [10]3 years ago

8 0

Answer:

The molecular weight of $Ca_3(PO_4)_2$ is 310.18 g/mol.

Explanation:

The molecular weight of $Ca_3(PO_4)_2$ :

Atomic mass of calcium = 40.08 g/mol

Atomic mass of phosphorous = 30.97 g/mol

Atomic mass of oxygen = 16.00 g/mol

Number of calcium atom = 3

Number of phosphorus atom =1 × 2

Number of oxygen atom =4 × 2 = 8

Molecular weight of $Ca_3(PO_4)_2$ = M

$M=3\times 40.08 g/mol+2\times 30.97g/mol+8\times 16.00g/mol$

M = 310.18 g/mol

Liula [17]3 years ago

3 0

Answer:

310.18g

Explanation:

The molar mass is 310.18 g/mol. To find the molar mass, you must find the atomic mass of each of the elements in the compound.

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