Answer:
<u>Point-slope form</u>: y - 8 = -9/2(x + 4)
Step-by-step explanation:
Given points (-4, 8) and (-2, -1)
In order to determine the point-slope form of the line, we must first solve for its slope by using the following formula:
m = (y2 - y1)/(x2 - x1)
Let (x1, y1) = (-4, 8)
(x2, y2) = (-2, -1)
Substitute these values into the slope formula:
m = (y2 - y1)/(x2 - x1)
m = (-1 - 8)/ [-2 (-4)]
m = -9/(-2 + 4)
m = -9/2
Therefore, the slope is m = -9/2.
Next, using the slope, m = -9/2, and one of the given points, (-4, 8), substitute these values into the point-slope form:
y - y1 = m(x - x1)
y - 8 = -9/2[x - (-4)]
y - 8 = -9/2(x + 4)
Please mark my answers as the Brainliest, if you find this solution helpful :)
7/8 times 8
7/8 times 8/1
56 over 8
divide 56 by 8
the answer is 7.25 or 7 if you are rounding
0.75 is the possible answer, if not its probably 12 :)
Answer:
mRP = 125°
mQS = 125°
mPQR = 235°
mRPQ = 305°
Step-by-step explanation:
Given that
Then:
- measure of arc RP, mRP = mROP = 125°
Given that
- ∠QOS and ∠ROP are vertical angles
Then:
- measure of arc QS, mQS = mROP = 125°
Given that
- ∠QOR and ∠SOP are vertical angles
Then:
Given that
- The addition of all central angles of a circle is 360°
Then:
mQOS + mROP + mQOR + mSOP = 360°
250° + 2mQOR = 360°
mQOR = (360°- 250°)/2
mQOR = mSOP = 55°
And (QOR and SOP are central angles):
- measure of arc QR, mQR = mQOR = 55°
- measure of arc SP, mSP = mSOP = 55°
Finally:
measure of arc PQR, mPQR = mQOR + mSOP + mQOS = 55° + 55° + 125° = 235°
measure of arc RPQ, mRPQ = mROP + mSOP + mQOS = 125° + 55° + 125° = 305°
Answer:
216 degrees
Step-by-step explanation:
9/15=0.6
0.6*360=216
