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Misha Larkins [42]
4 years ago
7

If point A is located at (-7,5) on a coordinate plane and point B is located at (4,5), what is the distance between the two poin

ts?
Mathematics
2 answers:
34kurt4 years ago
8 0

Answer: 11 units

Step-by-step explanation:

The distance between points P(a,b) and Q(c,d) is given by :-

d=\sqrt{(d-b)^2+(c-a)^2}

Similarly , the distance between the two points (-7,5) and (4,5) is given by :-

d=\sqrt{(5-5)^2+(4-(-7))^2}\\\\\Rightarrow\ d=\sqrt{0+(11)^2}=11

Hence, the the distance between the two points = 11 units

Svet_ta [14]4 years ago
3 0
I believe it's 13 units.
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5 0
3 years ago
Please help me with this
zhannawk [14.2K]
I’m pretty sure it’s 82
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2 years ago
Find a particular solution to the nonhomogeneous differential equation y′′+4y=cos(2x)+sin(2x).
I am Lyosha [343]
Take the homogeneous part and find the roots to the characteristic equation:

y''+4y=0\implies r^2+4=0\implies r=\pm2i

This means the characteristic solution is y_c=C_1\cos2x+C_2\sin2x.

Since the characteristic solution already contains both functions on the RHS of the ODE, you could try finding a solution via the method of undetermined coefficients of the form y_p=ax\cos2x+bx\sin2x. Finding the second derivative involves quite a few applications of the product rule, so I'll resort to a different method via variation of parameters.

With y_1=\cos2x and y_2=\sin2x, you're looking for a particular solution of the form y_p=u_1y_1+u_2y_2. The functions u_i satisfy

u_1=\displaystyle-\int\frac{y_2(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\int\frac{y_1(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx

where W(y_1,y_2) is the Wronskian determinant of the two characteristic solutions.

W(\cos2x,\sin2x)=\begin{bmatrix}\cos2x&\sin2x\\-2\cos2x&2\sin2x\end{vmatrix}=2

So you have

u_1=\displaystyle-\frac12\int(\sin2x(\cos2x+\sin2x))\,\mathrm dx
u_1=-\dfrac x4+\dfrac18\cos^22x+\dfrac1{16}\sin4x

u_2=\displaystyle\frac12\int(\cos2x(\cos2x+\sin2x))\,\mathrm dx
u_2=\dfrac x4-\dfrac18\cos^22x+\dfrac1{16}\sin4x

So you end up with a solution

u_1y_1+u_2y_2=\dfrac18\cos2x-\dfrac14x\cos2x+\dfrac14x\sin2x

but since \cos2x is already accounted for in the characteristic solution, the particular solution is then

y_p=-\dfrac14x\cos2x+\dfrac14x\sin2x

so that the general solution is

y=C_1\cos2x+C_2\sin2x-\dfrac14x\cos2x+\dfrac14x\sin2x
7 0
3 years ago
In triangle ABC, D is the midpoint of side AC and E is the midpoint of side BC.
cestrela7 [59]

Answer:

14

Step-by-step explanation:

Since all sides are half of greater triangle.Then 7 × 2 = 14 is length of greater hypotenuse.

Suppose two triangles with similar conditions

1^2+1^2=2

Hypotenuse=2^1/2

We assume another triangle which is exactly double of previous triangle I.e

2^2+2^2=8

Hypotenuse=2×2^1/2

Which is exactly twice of previous triangle.

Hence proved hyootenuse is double of smaller triangle I.e 14

8 0
3 years ago
Aight man can someone help me lol
uranmaximum [27]

Answer: 11/24

Step-by-step explanation:

whenever u see this — (

it means the opposite of. so the opposite of -5/8 is +5/8.

-1/6 + 5/8 = 11/24

4 0
3 years ago
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