Question

If point A is located at (-7,5) on a coordinate plane and point B is located at (4,5), what is the distance between the two points?

Answer 1

Answer: 11 units

Step-by-step explanation:

The distance between points P(a,b) and Q(c,d) is given by :-

$d=\sqrt{(d-b)^2+(c-a)^2}$

Similarly , the distance between the two points (-7,5) and (4,5) is given by :-

$d=\sqrt{(5-5)^2+(4-(-7))^2}\\\\\Rightarrow\ d=\sqrt{0+(11)^2}=11$

Hence, the the distance between the two points = 11 units

Answer 2

I believe it's 13 units.