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Viktor [21]
3 years ago
15

Write a program that prompts the user to enter a number then counts the number of odd numbers and even numbers the user enter. T

he program should exit if the user enter a zero or a number less than zero. For example, if the user enters 4, 7, 9, 8 21, 22, -1; upon entering -1 the program displays/output "3 even numbers and 3 odd numbers" were entered, then the program terminate
Computers and Technology
1 answer:
neonofarm [45]3 years ago
7 0

Answer:

The program written in Java is given in the explanation section

Explanation:

<em>import java.util.Scanner;</em>

<em>public class num3 {</em>

<em>    public static void main(String[] args) {</em>

<em>        Scanner in = new Scanner(System.in);</em>

<em>        System.out.println("This program counts evens and odds");</em>

<em>        System.out.println("To exit enter ZERO  or a NEGATIVE number");</em>

<em>        int num = in.nextInt();</em>

<em>        int numEvens=0;</em>

<em>        int numOdds = 0;</em>

<em>         while(num>=1){</em>

<em>             if(num%2==0){</em>

<em>              numEvens++;</em>

<em>             }</em>

<em>             else{</em>

<em>              numOdds++;</em>

<em>                }</em>

<em>             System.out.println("Enter the next number");</em>

<em>             num = in.nextInt();</em>

<em>            }</em>

<em>            System.out.println(numEvens+" even numbers and "+numOdds+" odd numbers");</em>

<em>    }</em>

<em>}</em>

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Zanzabum

Answer:

/*

Student: Hugo Meza

Date: February 15, 2019

Description: This program mimic the cat command from Linux. Checks whether the source file

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*/

#include <stdio.h>

#include <fcntl.h>

#include <unistd.h>

#include <errno.h>

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int returnval;

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return 0;

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else if (errno == EACCES){

printf ("%s is not accessible\n", filepath);

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if(errno == ENOENT){

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printf ("%s is not accessible\n",filepath);

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// Check write access

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else if (errno == EACCES){

printf ("%s is not accessible\n",filepath);

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int main(int argc, char* argv[]){

if(!argv[1]){

printf("Error. Specify file to open\n");

return 0;

}

int fd;

char *fp = argv[1], content[fd];

if(hasPermission(fp) == 0)

return 1;

fd = open(fp, O_RDONLY);

int bytes = read(fd,content,sizeof(content)-1);

write(1, content, bytes);

close(fd);

return 0;

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Explanation:

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Define function print_popcorn_time() with parameter bag_ounces. If bag_ounces is less than 3, print "Too small". If greater than
Gnoma [55]

Answer:

public static void print_popcorn_time(int bag_ounces){

       if(bag_ounces<3){

           System.out.println("Too Small");

       }

       else if(bag_ounces>10){

           System.out.println("Too Large");

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       else{

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           System.out.println(bag_ounces+" seconds");

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Explanation:

Using Java prograamming Language.

The Method (function) print_popcorn_time is defined to accept a single parameter of type int

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A complete java program calling the method is given below

public class num6 {

   public static void main(String[] args) {

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   }

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       else if(bag_ounces>10){

           System.out.println("Too Large");

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       else{

           bag_ounces*=6;

           System.out.println(bag_ounces+" seconds");

       }

   }

}

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