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LenKa [72]
3 years ago
6

Correct answers only please!

Mathematics
1 answer:
natali 33 [55]3 years ago
8 0

Answer:

  B.  10,000

Step-by-step explanation:

The volume of the jar is the product of its dimensions, so is ...

  V = LWH = (7 cm)(7 cm)(6.5 cm) = 318.5 cm³

If we assume there are 10 m&ms in one cm³ (probably, the number is more like 3 or 4), then there could be about 3,200 m&ms in the jar. The nearest reasonable limit of those proposed is ...

  10,000 . . . choice B

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Could someone please help ;(
Iteru [2.4K]

Answer:

a. 25/33

b. 36

c. 1/15

d. 35/12

e. 19/12

7 0
3 years ago
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Helpppppppppppppppppppppppppppppp! please someone?
Minchanka [31]

Answer:

-  \frac{16}{ 25 } \div ( -  \frac{4}{5} ) =  \frac{16}{25}  \times  \frac{5}{4}  =  \frac{4}{5}  \:or \: 0.8

4 0
3 years ago
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I can't seem to figure out number 13, with the star. I just don't know! Help is very appreciated ☺️
katrin2010 [14]
Given:
Scale of the map 1 1/4cm : 8 yards
Rectangular Park:  width : 2 1/2 cm ; length : 6 1/4 cm
Circular Pond: pi = 3.14 ; diameter 1 1/4 cm

Convert mixed factions into fractions.
Scale 1 1/4 = (4*1+1)/4 = 5/4
Width: 2 1/2 = (2*2+1)/2 = 5/2
Length: 6 1/4 = (4*6+1)/4 = 25/4
Diameter: 1 1/4 = (4*1+1)/4 = 5/4

width / scale * 8 yds = width in yards
5/2 ÷ 5/4 = 5/2 * 4/5 = 20/10 = 2 * 8 yds = 16 yds
length / scale * 8 yds = length in yards
25/4 ÷ 5/4 = 25/4 * 4/5 = 100/20 = 5 * 8 yds = 40 yds

Area of a rectangular park = l * w = 40 yds * 16 yds = 640 yds² 
 
diameter / scale * 8 yds = diameter in yards
5/4 ÷ 5/4 = 5/4 * 4/5 = 20/20 = 1 * 8 yds = 8 yds.

radius = d/2 = 8/2 = 4
Area of a circular pond = πr² = 3.14 * 4² = 3.14 * 16yds² = 50.24 yds²

5 0
3 years ago
Find the area of the shape shown below​
GuDViN [60]

Answer: 42 units squared

Step-by-step explanation:

3x7=21

3x7=21 divided by 2 = 10.5 + 10.5 = 21 so,

21+21=42

Hope it helps

3 0
3 years ago
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PLEASE HELP ITS URGENT!!<br> Given: △ABC is isosceles; 1 ≅ 3<br> Prove: AB || CD
Dmitrij [34]

Answer:

AB ║ CD. (Proved)

Step-by-step explanation:

See the attached diagram of the triangle.

It is given that Δ ACD is an isosceles triangle.

Therefore, AC = AD and ∠ ACD = ∠ ADC, ⇒ ∠ 3 = ∠ 4 .......... (1)

Again, given that ∠ 1 = ∠ 3 ........... (2)

Now, from equations (1) and (2) we can write, ∠ 1 = ∠ 4

Now, AB and CD are two straight lines and AD is the transverse line and hence, ∠ 1 and ∠ 4 are alternate angles that are equal.

Therefore, AB and CD are parallel straight lines and AB ║ CD. (Proved)

4 0
4 years ago
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