Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify!
You need to know three exponent rules to simplify these expressions:
1)
The
negative exponent rule says that when a
base has a negative exponent, flip the base onto the other side of the
fraction to make it into a positive exponent. For example,

.
2)
Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example,

.
3) The
zero exponent rule<span> says that any number
raised to zero is 1. For example,

.
</span>
Back to the Problem:
Problem 1
The x-values are in the left column. The title of the right column tells you that the function is

. The x-values are:
<span>
1) x = 0</span>Plug this into

to find letter a:

<span>
2) x = 2</span>Plug this into

to find letter b:

<span>
3) x = 4</span>Plug this into

to find letter c:

<span>
Problem 2
</span>The x-values are in the left column. The title of the right column tells you that the function is

. The x-values are:
<span>
1) x = 0</span>Plug this into

to find letter d:

<span>
2) x = 2
</span>Plug this into

to find letter e:

<span>
3) x = 4
</span>Plug this into

to find letter f:

<span>
-------
Answers: a = 1b = </span>

<span>
c = </span>
d = 1e =
f =
Since the sum of the probabilities of all possible outcomes must be 100%, we can deduce the following:
- Cooking in under 20 minutes: 10%
- Cooking between 20 and 30 minutes: 85%
- Cooking in more than 30 minutes: 5%
In fact, the probabilities of cooking in less than 20 or more than 30 sum up to 15%, which means that the remaining outcome (i.e. cooking time between 20 and 30) must complete this probability to 15, and in fact 15+85=100.
That being said, all three answers are simply a combination of these three scenarios: let C be the cooking time, for aesthetic reasons:



The required inequality is 
<em><u>Solution:</u></em>
Given that,
Cost of 1 cap = $ 5
Cost of 1 t-shirt = $ 10
Let "x" be the number of caps sold
Let "y" be the number of t-shirts sold
The drama club needs to raise at least $500.00 for the trip
Based on this information, we can frame a inequality as:
number of caps sold x cost of 1 cap + number of shirts sold x cost of 1 shirt
500
Which means,

Here we used "greater than or equal to" symbol , because club needs to raise at least $ 500
They can raise 500 or more than $ 500 also
Thus the required inequality is 
Answer:
The kind of error the researcher has done is a;
Type I error
Step-by-step explanation:
When carrying out hypothesis testing in statistical analysis, a type I error is the type of error said to have occurred when a null hypothesis that is true or correct is rejected which is a false positive conclusion
Given that that sugar box manufacturing company makes the boxes to be 100 g accurately, and that the researcher makes non-random or randomly selects packets which are not filled, the mean of the filled packets is expected to be 100 g making the conclusion for rejection of the null hypothesis a false positive rejection