All categories

3 years ago

Please helpp! I need help ASAP!!

Mathematics

1 answer:

Alexeev081 [22]3 years ago

3 0

i think its f But im not sure just try doing it because i dont understand it that well

You might be interested in

How do you solve x 1/2 power + 2

nirvana33 [79]

It probably is 2 1/4 because 1/2 to the second power is 1/4 then added to 2 will be 2 1/4. Hope this helps! Good Luck with your homework!!!

8 0

3 years ago

What is the equation of the line that passes through the point (3,-1) and is perpendicular to the equation y= -3x+2?

Sauron [17]

Answer:

i think it is b or d im not for sure though

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The number of girls who work at Super Shopper is 4 more than 2 times the number of boys. If 30 boys work at Super Shopper, how m

Oxana [17]

Answer:

I'm pretty sure it's 92!

7 0

2 years ago

Customers arrive at a movie theater at the advertised movie time only to find that they have to sit through several previews and

balu736 [363]

Answer:

(a) The sample size required is 43.

(b) The sample size required is 62.

Step-by-step explanation:

The (1 - α) % confidence interval for population mean is:

$CI=\bar x\pm z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}$

The margin of error for this interval is:

$MOE=z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}$

(a)

The information provided is:

<em>σ</em> = 4 minutes

MOE = 72 seconds = 1.2 minutes

Confidence level = 95%

α = 5%

Compute the critical value of z for α = 5% as follows:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use a z-table.

Compute the sample size required as follows:

$MOE=z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}$

$n=[\frac{z_{\alpha/2}\times \sigma}{MOE} ]^{2}$

$=[\frac{1.96\times 4}{1.2}]^{2}\\\\=42.684\\\\\approx 43$

Thus, the sample size required is 43.

(b)

The information provided is:

<em>σ</em> = 4 minutes

MOE = 1 minute

Confidence level = 95%

α = 5%

Compute the critical value of z for α = 5% as follows:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use a z-table.

Compute the sample size required as follows:

$MOE=z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}$

$n=[\frac{z_{\alpha/2}\times \sigma}{MOE} ]^{2}$

$=[\frac{1.96\times 4}{1}]^{2}\\\\=61.4656\\\\\approx 62$

Thus, the sample size required is 62.

3 0

3 years ago

How many terms are in the expression 4a + 3b + c

Ludmilka [50]

3 terms

https://youtu.be/0sq2PMQ_Nak
use that video to help you.

4 0

3 years ago

Read 2 more answers