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inna [77]
3 years ago
10

I need help on these questions please

Mathematics
1 answer:
Paraphin [41]3 years ago
7 0

Answer:

Step-by-step explanation:

1). In ΔABC,

   For angle A as a reference angle,

   Opposite side of ∠A → BC

   Adjacent side of ∠A → AC

   Hypotenuse → AB

2). By using tangent ratio in ΔYWZ,

    tan(72°) = \frac{\text{Opposite side}}{\text{Adjacent side}}

    tan(72°) = \frac{12}{x}

    x = \frac{12}{\text{tan}(72)}

    x = 3.899

    x ≈ 3.9

3). By using sine rule in ΔKNM,

    tan(x°) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

    tan(x) = \frac{20}{58}

    x = \text{tan}^{-1}(\frac{20}{58} )

    x = 19.03

    x ≈ 19.0°

4). By applying cosine ratio in ΔJKF,

    tan(70°) = \frac{\text{Opposite side}}{\text{Adjacent side}}

    tan(70) = \frac{60}{x}

    x = \frac{60}{\text{tan}(70)}

    x = 21.838

    x ≈ 21.8

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