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KiRa [710]
3 years ago
9

The diameter of a circle is 24 centimeters. What is the circle's area?

Mathematics
1 answer:
ch4aika [34]3 years ago
8 0

Answer:

The diameter is 24 so the radius is 12 then we do pi*r^2 or pi*12^2

We can use our numbers and get pi*144 so the area of the circle is 144pi.

If they have given you what pi is

EX:( 22/7 or 3.14)

Just use that instead of pi and multiply 144 to that

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Only answer if you are 100% sure about the answer.
hram777 [196]

Answer:

180

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A school has 200 students and spends $40 on supplies for each student. The principal expects the number of students to increase
Xelga [282]

Answer:

\mathbf{S(t)=200(\frac{105}{100})^{x}}

\mathbf{A(t)=40(\frac{98}{100})^{x}}

\mathbf{E(t)=S(t) \cdot A(t)=200(\frac{105}{100})^{x} \cdot 40(\frac{98}{100})^{x}=8000(\frac{10290}{10000})^{x}}

Step-by-step explanation:

<h3>The predicted number of students over time, S(t) </h3>

Rate of increment is 5% per year.  

A function 'S(t)' which gives the number of students in school after 't' years.  

S(0) means the initial year when the number of students is 200.

S(0) = 200  

S(1) means the number of students in school after one year when the number increased by 5% than previous year which is 200.  

S(1) = 200 + 5% of 200 = 200+\frac{5}{100}\time200 = 200(1+\frac{5}{100}) = 200(\frac{105}{100})  

S(2) means the number of students in school after two year when the number increased by 5% than previous year which is S(1)  

S(2) = S(1) + 5% of S(1) = \textrm{S}(1)(\frac{105}{100}) = 200(\frac{105}{100})(\frac{105}{100}) = 200(\frac{105}{100})^{2}  

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.  

.  

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Similarly \mathbf{S(x)=200(\frac{105}{100})^{x}}  

<h3>The predicted amount spent per student over time, A(t) </h3>

Rate of decrements is 2% per year.  

A function 'A(t)' which gives the amount spend on each student in school after 't' years.  

A(0) means the initial year when the number of students is 40.  

A(0) = 40  

A(1) means the amount spend on each student in school after one year when the amount decreased by 2% than previous year which is 40.  

A(1) = 40 + 2% of 40 = 40-\frac{2}{100}\time40 = 40(1-\frac{2}{100}) = 40(\frac{98}{100})  

A(2) means the amount spend on each student in school after two year when the amount decreased by 2% than previous year which is A(1)  

A(2) = A(1) + 2% of A(1) = \textrm{A}(1)(\frac{98}{100}) = 40(\frac{98}{100})(\frac{98}{100}) = 40(\frac{98}{100})^{2}  

.  

.  

.  

.  

.  

Similarly \mathbf{A(x)=40(\frac{98}{100})^{x}}  

<h3>The predicted total expense for supplies each year over time, E(t)</h3>

Total expense = (number of students) ×  (amount spend on each student)

E(t) = S(t) × A(t)

\mathbf{E(t)=S(t) \cdot A(t)=200(\frac{105}{100})^{x} \cdot 40(\frac{98}{100})^{x}=8000(\frac{10290}{10000})^{x}}

\mathbf{E(t)=8000(\frac{10290}{10000})^{x}}

(NOTE : The value of x in all the above equation is between zero(0) to ten(10).)

6 0
3 years ago
Read 2 more answers
the average walking speed of a person is 4.8 kilometersper hour. estimate the number of kilometers could you walk in 3 hours?
Rus_ich [418]
14.4 Kilometers per hour.
6 0
3 years ago
Please help! I'm getting timed.
Kobotan [32]
The answer is A. It has side lengths of 3.
5 0
3 years ago
Suppose that poaching reduces the population of an endangered animal by 8​% per year. Further suppose that when the population o
ohaa [14]

Answer:  36 years

Step-by-step explanation:

Here, the current population of the animal is 1400​,

And, the  population of an endangered animal by 8​% per year.

Also, Further suppose that when the population of this animal falls below 70​, its extinction is inevitable​.

Let after x years the population of animal falls below 70,

Therefore, 1400(1-\frac{8}{100} )^x < 70

⇒ (\frac{92}{100})^x < \frac{70}{1400}

⇒ (\frac{92}{100})^x < \frac{1}{20}

⇒ x log(.92) < log(0.5)

⇒- 0.03621217265 x < -1.30102999566

⇒x>35.9279739462

Thus, after 36 years( Approx) the population of the animal will be fall towards 70.

6 0
3 years ago
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