Answer:
f(g(x)) = 3(2x^3 -2)^2 - 4x + 2, and f(g(3)) = 3[2(3)^3 -2]^2 -4*3 -2 = 8102
Step-by-step explanation:
because for f(g(x)), the g(x) is the input of f(x), so put 2x^3 -2 into 3x^2 -4x +2, and you will get f(g(x)). because g(3) is the input of f(x), so find g(3) first, the answer is 52, and then put it back into f(x) which will be f(52) =[3(52)^2 - 4(3) +2], then the answer should be 8102.
IQR = 40
1) Put the numbers in order: 40, 45, 50, 60, 60, 75, 90, 90, 120
2) Find the median: Median is 60 (the 2nd one)
3) Place parentheses around the numbers above and below the median. For easy identification of Q1 and Q3. (40, 45, 50, 60,) 60, (75, 90, 90, 120)
4) Find the Q1 and Q3. Q1 = median of the lower half of the data; Q3 = median of the higher half of the data. Q1 and Q3 have even sets so its median cannot be defined.
5) Had both sets contain odd sets, the median of Q1 is subtracted from the median of Q3 to get the IQR.
We can then use the Alternative definition of IQR.
IQR is the difference between the largest and smallest values in the middle 50% of a set data.
40, 45, 50, 60, 60, 75, 90, 90, 120
Middle 50% is 50, 60, 60, 75, 90; IQR = Largest value - smallest value;
IQR = 90 - 50 = 40
The answer is B.g(x) hope it helped!!
Answer:
- Tadeo: 12 hours
- Dylan: 2 hours
Step-by-step explanation:
We can let d represent the number of hours that Dylan volunteered. Then Tadeo volunteered for 6d hours, and their total hours were ...
d +6d = 14
7d = 14 . . . . . . collect terms
d = 2 . . . . . . . divide by the coefficient of d
6d = 6(2) = 12
Tadeo volunteered 12 hours; Dylan volunteered 2 hours.
