Step-by-step explanation: need to find a basis for the solutions to the equation Ax = 0. To do this ... 0 0 0 1 −3. ⎤. ⎦. From this we can read the general solution, x = ⎡. ⎢. ⎢. ⎢. ⎢. ⎣ ... two vectors are clearly not multiples of one another, they also give a basis. So a basis ... 4.4.14 The set B = {1 − t2,t − t2,2 − 2t + t2} is a basis for P2.
What are you asking to solve?
Answer:
△NPK≅△HBG; and △KNP≅△GHB
Explanation:
Using the given congruence statement, we can determine corresponding pieces of the triangles:
P corresponds to B; K corresponds to G; and N corresponds to H.
This means that △NKP≅△HGB, not HBG.
△KPN≅△GBH, not BHG.
△NPK≅△HBG; this is correct.
△KNP≅△GHB; this is correct.