Answer:
20
Step-by-step explanation:
When you add them all up and divide by seven, you get 20
The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
What is the intermediate value theorem?
Intermediate value theorem is theorem about all possible y-value in between two known y-value.
x-intercepts
-x^2 + x + 2 = 0
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x = -1, x = 2
y intercepts
f(0) = -x^2 + x + 2
f(0) = -0^2 + 0 + 2
f(0) = 2
(Graph attached)
From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3
For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.
<em>Your question is not complete, but most probably your full questions was</em>
<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>
Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
Learn more about intermediate value theorem here:
brainly.com/question/28048895
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Let's name the x-coordinates and y-coordinates
- x-coordinate = abscicca
- y-coordinate = ordinate
So, According to question
- Abscicca of Point D = Ordinate of Point B
- Ordinate of Point D = Abscicca of Point A
Abscicca of Point A = 2
Ordinate of Point B = -4
<h3>Thus, </h3>
Point D = (-4,2)
61/8 or 7 and 5/8. I would try either one
Step-by-step explanation:
22x13, 10x9, then both answers from the previous equations multiplied. Any questions?