False .........................................
Answer:
n = 0.207 mole
Explanation:
We have,
P = 1 atm
V = 5 liter
R = 0.0821 L.atm/mol.K
T = 293 K
We need to find the value of n. The relation is as follows :
PV = nRT
Solving for n,

So, the value of n is 0.207 mol.
Answer:
4Fe+ 6H2 O+ 3O2 ----> 4Fe(OH)3
1.34 grams of MgNH4PO4*6H2O
Molar mass= 245.1 grams per mole
Moles of MgNH4PO4*6H2O=
(1.34 grams)(1 mole/245.1 grams fertilizer)=0.0054671563 moles fertilizer
MgNH4PO4*6H2O has 1 mole of Phosphorous, so:
0.0054671563 moles fertilizer(1 mole Phosphorous/1 mole fertilizer)
0.0054671563 moles Phosphorous (30.97 grams/ 1 mole)
=0.1693178295 grams Phosphorous