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Hitman42 [59]
4 years ago
13

What is stratosphere

Chemistry
1 answer:
____ [38]4 years ago
4 0
The stratosphere is above the earth's troposphere. It is about 32 miles above the earth's surface.

Have a nice day! :)
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RNA stands for A. really not awesome B. ribonucleic acid C. ribosomes not active
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B. ribonucleic acid is the answer your looking for
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3 years ago
Which of the following shows the energy transformation that
const2013 [10]

Answer: either B, or D

Explanation:

because one of those are the answer

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Which of the following is the highest level of organization (least specific)? a. genus c. family b. class d. order
yKpoI14uk [10]
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Your answer would be:

a. genus
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3 years ago
The second-order rate constant for the dimerization of a protein (P) P + P → P2 is 6.2 × 10−3/M · s at 25°C. Part 1 out of 2 If
siniylev [52]

Answer:

r=1.59\times 10^{-10}\ M/s

Explanation:

According to the law of mass action:-

The rate of the reaction is directly proportional to the active concentration of the reactant which each are raised to the experimentally determined coefficients which are known as orders. The rate is determined by the slowest step in the reaction mechanics.

Order of in the mass action law is the coefficient which is raised to the active concentration of the reactants. It is experimentally determined and can be zero, positive negative or fractional.

The order of the whole reaction is the sum of the order of each reactant which is raised to its power in the rate law.

From the reaction given that:-

P+P\rightarrown P_2

The expression for the rate is:-

r=k[P]^2

Given that;- k= 6.2\times 10^{-3} /Ms

[P] = 1.6\times 10^{-4} M

Thus,

r=6.2\times \:10^{-3}\times \:\left(1.6\times \:\:10^{-4}\right)^2\ M/s=1.59\times 10^{-10}\ M/s

8 0
3 years ago
A sample of an unknown gas effuses in 14.4 min. An equal volume of H2 in the same apparatus under the same conditions effuses in
Elena-2011 [213]

Answer:- molar mass of the unknown gas is 71.5 gram per mol.

Solution:- From Graham's law of effusion rates, the rate of effusion of a gas is inversely proportional to the square root of it's molar mass.

When we compare the effusion rates of two gases then the formula for Graham's law is:

\frac{rate_1}{rate_2}=\sqrt{\frac{M_2}{M_1}}

In this formula, V stands for volume and M stands for molar mass

Rate is volume effused per unit time. Since, the volumes are same, the formula could be written as:

\frac{t_2}{t_1}=\sqrt{\frac{M_2}{M_1}}

let's say in formula, subscript 1 is for hydrogen gas and 2 is for the unknown gas.

Molar mass of hydrogen is 2.02 grams per mol and the time taken to effuse it is 2.42 min. The time taken to effuse the unknown gas is 14.4 min and we are asked to calculate it's molar mass. let's plug in the values in the formula:

\frac{14.4}{2.42}=\sqrt{\frac{M_2}{2.02}}

5.95=\sqrt{\frac{M_2}{2.02}}

doing squares to both sides:

35.4=\frac{M_2}{2.02}

M_2=35.4*2.02

M_2=71.5

So, the molar mass of the unknown gas is 71.5 grams per mol.



4 0
3 years ago
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