Is the first number divisible by the second 790 by 2

DOES ANYONE KNOW THIS?????

dedylja [7]

Answer:

if i;m right its 45 degrees

Step-by-step explanation:

5 0

4 years ago

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Suppose researchers test 100 college students, whose ages range from 18 to 23. They also test 100 people at a nearby community c

prisoha [69]

Answer:

b. You would conclude that the differences in the average scores can be traced to differences in the working memory of the two groups.

Step-by-step explanation:

Though the average scores of the two sets could have lead to various conditions, but retentive ability deminishes with respect to an increase in age. With respect to the age of the elderly people involved, it is expected that some of them would not be able to retain information for a long period of time. Thus, their average score is 72%.

The college students' are younger, so it is expected that they should be able to retain more information. That ability is one of the reasons why their average score is 85%.

It can be concluded from the research that the differences in the average scores is probably due to the working memory of the two groups.

6 0

3 years ago

A food processor packages orange juice in small jars. The weights of the filled jars are approximately normally distributed with

Ratling [72]

Answer:

$P(X>10.983)=P(\frac{X-\mu}{\sigma}>\frac{10.983-\mu}{\sigma})=P(Z>\frac{10.983-10.5}{0.3})=P(z>1.61)$

And we can find this probability using the complement rule and with excel or the normal standard table:

$P(z>1.61)=1-P(z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(10.5,0.3)$