<img src="https://tex.z-dn.net/?f=%28%20-%208x%7D%5E%7B2%7D%20%20-%205x%20-%206%29%20%2B%20%28%20-%20x%20%7B%20%7D%5E%7B2%7D%20-

All categories

3 years ago

%20x%20%2B%205%29" id="TexFormula1" title="( - 8x}^{2} - 5x - 6) + ( - x { }^{2} - x + 5)" alt="( - 8x}^{2} - 5x - 6) + ( - x { }^{2} - x + 5)" align="absmiddle" class="latex-formula">
Solve

Mathematics

1 answer:

Jlenok [28]3 years ago

8 0

Hello! I hope this helps! <33

Answer:

-9x^2-6x-1

Step-by-step explanation:

1.) Remove parantheses

-8x^2-5x-6-x^2-x+5

2.) Group like terms

8x^2-x^2-5x-x-6+5

3.) Add similar elements

-9x^2-5x-x-6+5

4.) Add similar elements

-9x^2-6x-6+5

Answer = -9x^2-6x-6+5

Have a nice day! ;)

You might be interested in

What is 190% of 66? Round to the nearest hundredth.

Aneli [31]

Answer:

190% of 66= 125.4

rounded to the nearest tenth:130

4 0

3 years ago

Moby sold half his toy car collection, and then bought 12 more cars the next day. He now has 48 toy cars. How many cars did he h

castortr0y [4]

Answer: 72 cars.

Step-by-step explanation:

Let be "x" the number of toys that Moby had to start with.

According to the information given in the exercise, Moby sold half his toy car collection. This can be represented with the following expression:

$\frac{1}{2}x$

Then he bought 12 more cars, giving a total amount of 48 toy cars.

Therefore, the equation that represents this situation is the equation shown below:

$x-\frac{1}{2}x+12=48$

Now you must solve for "x" in order to find its value.

You get that this is:

$\frac{1}{2}x+12=48\\\\\frac{1}{2}x=48-12\\\\\frac{1}{2}x=36\\\\x=(36)(2)\\\\x=72$

7 0

3 years ago

Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the curves about the given

Fed [463]

See attachment for one such shell. The volume is given by the sum of infinitely many thin shells like this, each with radius $x$ and height determined by the vertical distance between the upper blue curve and the lower orange curve for any given $x$ , i.e. $8e^x-8e^{-x}$ .

The volume is then

$2\pi\displaystyle\int_0^1x\left(8e^x-8e^{-x}\right)\,\mathrm dx=16\pi\int xe^x(e^{2x}-1)\,\mathrm dx=\dfrac{32\pi}9(e^3-4)\approx179.677$