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Lera25 [3.4K]
3 years ago
6

If a straight angle is bisected,the resulting angles are?

Mathematics
2 answers:
MissTica3 years ago
8 0
Yes, if you have a straight angle (which is bisected) the angles you have left or the resulting angles are too
nasty-shy [4]3 years ago
4 0
A straight angle is 180 degrees but once it's bisected, each angle is 90 degrees - right angles. 

<span>An obtuse angle bisected would give you two acute angles.</span>
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Solve the following system of equations.<br><br> 2x-3y=8<br> -2x+6y=-20
wolverine [178]
Solve the following system:
{2 x - 3 y = 8 | (equation 1)
{6 y - 2 x = -20 | (equation 2)

Add equation 1 to equation 2:
{2 x - 3 y = 8 | (equation 1)
{0 x+3 y = -12 | (equation 2)

Divide equation 2 by 3:
{2 x - 3 y = 8 | (equation 1)
{0 x+y = -4 | (equation 2)


Add 3 × (equation 2) to equation 1:
{2 x+0 y = -4 | (equation 1)
{0 x+y = -4 | (equation 2)

Divide equation 1 by 2:
{x+0 y = -2 | (equation 1)
{0 x+y = -4 | (equation 2)

Collect results:
Answer:  {x = -2
                {y = -4
3 0
3 years ago
I need help, please im stuck on this problem
sergij07 [2.7K]

Answer:

4 yards

Step-by-step explanation:

divide it by 3

6 0
3 years ago
Read 2 more answers
All of the following are benefits (the "pro's") of having a credit card, EXCEPT which one?
aliina [53]
I think it’s E - or C
8 0
3 years ago
A Food Marketing Institute found that 29% of households spend more than $125 a week on groceries. Assume the population proporti
ella [17]

Using the normal distribution, there is a 0.7357 = 73.57% probability that the sample proportion of households spending more than $125 a week is less than 0.31.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1 - p)}{n}}, as long as np \geq 10 and n(1 - p) \geq 10.

The estimate and the sample size are:

p = 0.29, n = 207.

Hence the mean and the standard error are given as follows:

  • \mu = p = 0.29.
  • s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.29(0.71)}{207}} = 0.0315.

The probability that the sample proportion of households spending more than $125 a week is less than 0.31 is the <u>p-value of Z when X = 0.31</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem:

Z = \frac{X - \mu}{s}

Z = \frac{0.31 - 0.29}{0.0315}

Z = 0.63

Z = 0.63 has a p-value of 0.7357.

0.7357 = 73.57% probability that the sample proportion of households spending more than $125 a week is less than 0.31.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

6 0
2 years ago
After 1 second, the missile is 130 feet in the air; after 2 seconds, it is 240 feet in the air.
CaHeK987 [17]
Ok so what is the question here<span />
3 0
3 years ago
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