Solve the following system:
{2 x - 3 y = 8 | (equation 1)
{6 y - 2 x = -20 | (equation 2)
Add equation 1 to equation 2:
{2 x - 3 y = 8 | (equation 1)
{0 x+3 y = -12 | (equation 2)
Divide equation 2 by 3:
{2 x - 3 y = 8 | (equation 1)
{0 x+y = -4 | (equation 2)
Add 3 × (equation 2) to equation 1:
{2 x+0 y = -4 | (equation 1)
{0 x+y = -4 | (equation 2)
Divide equation 1 by 2:
{x+0 y = -2 | (equation 1)
{0 x+y = -4 | (equation 2)
Collect results:
Answer: {x = -2
{y = -4
Answer:
4 yards
Step-by-step explanation:
divide it by 3
Using the normal distribution, there is a 0.7357 = 73.57% probability that the sample proportion of households spending more than $125 a week is less than 0.31.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
- By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean
and standard deviation
, as long as
and
.
The estimate and the sample size are:
p = 0.29, n = 207.
Hence the mean and the standard error are given as follows:
.
.
The probability that the sample proportion of households spending more than $125 a week is less than 0.31 is the <u>p-value of Z when X = 0.31</u>, hence:

By the Central Limit Theorem:


Z = 0.63
Z = 0.63 has a p-value of 0.7357.
0.7357 = 73.57% probability that the sample proportion of households spending more than $125 a week is less than 0.31.
More can be learned about the normal distribution at brainly.com/question/4079902
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