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Dafna1 [17]
3 years ago
7

List the perfect cubes that are between 100 and 600

Mathematics
1 answer:
DochEvi [55]3 years ago
3 0
125<span>, </span>216<span>, </span>343<span>, </span><span>512 are perfect cubes</span>
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What number is 9.5% of 20?
mars1129 [50]
1.9


9.5% = 0.095

0.095* 20 = 1.9
7 0
3 years ago
plant a is 5 centimeters tall and going at the rate of 3 centimeters in a month. plan B is 4 centimeters tall and growing at the
pav-90 [236]

I need more information sorry

3 0
4 years ago
A fixed asset with a five-year estimated useful life and no residual value is sold at the end of the second year of its useful l
DerKrebs [107]

Answer:

Gain: (Decrease)

Loss:

(Increase)

Step-by-step explanation:

5 0
3 years ago
If a1=2 and an=2an-1 find the first 5 sequences
Murljashka [212]

Answer:

The first 5 terms of the sequence are 2, 4, 8, 16 and 32.

Step-by-step explanation:

Given:

a_{1} = 2

a_{n} = 2a_{n-1}   -----------------(i)

To get the first 5 terms of the sequence, substitute in turn, n = 1, 2, 3, 4, 5 into equation (i).

The first term (when n = 1) has been given as:

a_{1} = 2

The second term (when n = 2) is given as:

a_{2} = 2a_{2-1}

a_{2} = 2a_{1}    (but a_{1} = 2 )

=> a_{2} = 2(2)

=> a_{2} = 4

The third term (when n = 3) is given as:

a_{3} = 2a_{3-1}

a_{3} = 2a_{2}    (but a_{2} = 4 )

=> a_{3} = 2(4)

=> a_{3} = 8

The fourth term (when n = 4) is given as:

a_{4} = 2a_{4-1}

a_{4} = 2a_{3}   (but a_{3} = 8 )

=> a_{4} = 2(8)

=> a_{4} = 16

The fifth term (when n = 5) is given as:

a_{5} = 2a_{5-1}

a_{5} = 2a_{4}   (but a_{4} = 16 )

=> a_{5} = 2(16)

=> a_{5} = 32

Therefore, the first 5 terms of the sequence are 2, 4, 8, 16 and 32.

5 0
3 years ago
An economist wants to estimate the mean per capita income (in thousands of dollars) for a major city in California.
pishuonlain [190]

Answer:

The 80% confidence interval for the mean per capita income in thousands of dollars is between $21.3 and $21.9.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.8}{2} = 0.1

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.1 = 0.9, so z = 1.28

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.28*\frac{12.5}{\sqrt{3839}} = 0.3

The lower end of the interval is the sample mean subtracted by M. So it is 21.6 - 0.3 = $21.3.

The upper end of the interval is the sample mean added to M. So it is 21.6 + 0.3 = $21.9.

The 80% confidence interval for the mean per capita income in thousands of dollars is between $21.3 and $21.9.

7 0
3 years ago
Read 2 more answers
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