2 years ago

N+4=-2 solve equation

Mathematics

2 answers:

erastovalidia [21]2 years ago

8 0

Answer:

-6

Step-by-step explanation:

N+4=-2

=>N=-2-4 (subtracting 4 from both sides)

=>N=-6

plz mark me as brainliest

exis [7]2 years ago

5 0

Answer:

n=-6

Step-by-step explanation:

n+4=-2

1. Move the -4 to the other side of the equal sign.

n=-2-4

2. Calculate -2-4 to get -6

You might be interested in

7% of 120 (Need work shown)

inessss [21]

1% of 120 is 1.2, so 7 *1.2 = 8.4

Also you could set up the proportion 7/100 = x/120 and solve for x.

3 0

2 years ago

Read 2 more answers

Put the following list of numbers in ascending order.<br> 1.2 0, -0.4, -2.6, 0

Elza [17]

Answer:

-2.6, -0.4, 0, 1.2

Step-by-step explanation:

tell me if i'm wrong :)

8 0

3 years ago

Read 2 more answers

(I think I know it just checking) Which function has a period equal to half the period of the function in y=5cos(3/5x-pi)+4.. th

eduard

Answer:

A is your answer

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Jaya's coach agreed to buy ice

german

I don’t understand what this is

6 0

3 years ago

8x2 − 5 + 7x4 − 9x − x5

Veseljchak [2.6K]

Answer:

$=-\left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)$

Step-by-step explanation:

Factor out comon Term -1

$=-\left(x^5-7x^4-8x^2+9x+5\right)$

Factor $x^5-7x^4-8x^2+9x+5:\quad \left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)$

$x^5-7x^4-8x^2+9x+5$

Use the rational root theorem

$a_0=5,\:\quad a_n=1$

The dividers of $a_{0}$ : 1, 5, The dividers of $a_n$ : 1

Therefore, check the following rational numbers: ± $\frac{1,\:5}{1}$

$\frac{1}{1}$ is a root of the expression, so factor out $x-1$

$=\left(x-1\right)\frac{x^5-7x^4-8x^2+9x+5}{x-1}$

$\frac{x^5-7x^4-8x^2+9x+5}{x-1}=x^4-6x^3-6x^2-14x-5$

$=x^4-6x^3-6x^2-14x-5$

$=-\left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)$

8 0

3 years ago