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Scorpion4ik [409]
2 years ago
5

What’s the Variace of 7, 5, 11, 1, 11

Mathematics
1 answer:
lara31 [8.8K]2 years ago
8 0
The mean is 35/5=7

v=((7-7)^2+(5-7)^2+(11-7)^2+(1-7)^2+(11-7)^2)/5

v=(0+4+16+36+16)/5

v=14.4
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Twice the larger of two consecutive integers is equal to fifteen less than three times the smaller. Find the integers.
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Answer:

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Step-by-step explanation:

let the smaller integer be "a" and the larger be "b"

Then 2b = 3a -15              ........................equ 1

but they are consecutive integers, b= a+1 ; substitute b into equ 1,thus,

2(a+1) = 3a - 15

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collect like terms,

2+15 =3a-2a

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b = 17+1

b=18.

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