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Scorpion4ik [409]
3 years ago
5

What’s the Variace of 7, 5, 11, 1, 11

Mathematics
1 answer:
lara31 [8.8K]3 years ago
8 0
The mean is 35/5=7

v=((7-7)^2+(5-7)^2+(11-7)^2+(1-7)^2+(11-7)^2)/5

v=(0+4+16+36+16)/5

v=14.4
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A 150-N bird feeder is supported by three cables. Find the tension in each cable.
Irina-Kira [14]
X axis : -t1 cos 60 + t2 cos 60 = 0
 
            t2 cos 60   = t1 cos 60    ; t2   = t1

Y axis : t1 sin 60  + t2 sin 60 - 150 = 0

since t2 = t1

2t1 sin 60 =  150

t1 ( sqrt(3)/2)  = 150/2

t1   = 50 [sqrt(3)]

t2 = 50 [sqrt(3)]

t3 = 150 N

hope this helps


6 0
3 years ago
Read 2 more answers
What is the distance between (-3, 4) and (4, 4)
svetoff [14.1K]

Answer:

7 units

Step-by-step explanation:

\sqrt{|-3-4|^{2}-|4-4|^{2}}

=7

3 0
3 years ago
Read 2 more answers
Subtract and simplify: 4y/y^2-10y+21-1/y-3
Eva8 [605]
OK...... your answer would be

- 10y^2 - 26y + 1/y
H0P3 It H3LPS :)
3 0
4 years ago
A linear pair of<br> angles have<br> measures of 3m - 6<br> and 3m + 18. What<br> is the value of m?
timama [110]

Answer:

the value of m = 28°

Step-by-step explanation:

the sum of adjacent angles which form linear pair is 180°

so,

=》3m - 6° + 3m + 18° = 180°

=》6m + 12° = 180°

=》6m = 180° - 12°

=》m = 168° ÷ 6

=》m = 28°

4 0
3 years ago
A chemist is using 351 millimeters of a solution of acid and water. If 18.2% of the solution is acid, how many milliliters of ac
Zolol [24]

Answer:

The % of of acid in solution  = 63.88 ml

Step-by-step explanation:

The solution of acid and water = 351 milliliters

The % of of acid in solution  = 18.2% of 351 ml

Or, The % of of acid in solution  = \frac{18.2}{100} × 351 ml

Or, The % of of acid in solution  = 63.882 ml

Hence ,The % of of acid in solution  = 63.88 ml  Answer

3 0
4 years ago
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