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Grace [21]
3 years ago
13

What are some of the cities where jazz first developed during the 1920s and 1930s? Why do you think these particular cities beca

me important sites for jazz? From the timeline, on the left choose one subgenre of jazz and discuss what elements are found in this type of music. Choose one decade from the timeline on the left, and discuss how that particular decade influenced the development of jazz music. What is hard bop? What is jazz fusion? What is jazz like today? After listening to some of the music from different jazz composers, which one do you like the best? Why?
Mathematics
1 answer:
Rus_ich [418]3 years ago
6 0

Answer:

Although New Orleans is usually credited with being the birthplace of jazz, similar music also began happening not long after in other cities, including Chicago, Kansas City, and Saint Louis.

Step-by-step explanation:

hope it helps but it is not all the answers .

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Please help veryyy urgent due today!!!!!!
Musya8 [376]
42 is the answer....
4 0
2 years ago
Blake and two friends equally shared the cups of water shown in the picture.
3241004551 [841]
The answer would be c- 2/6

there are six cups total and three (blake plus two others) friends

there are two ways you can solve this…

1. by making groups
if you look at the picture, you can split it into three groups because that is the number of people, then count how many cups there are in one group which will be your numerator for the denominator six which is the total

2. simple division
divide the total number of cups buy the number of people which is 3
you get two and follow the same process above

6 0
2 years ago
Need help asapdue today at 11 am
goblinko [34]

12 ×  8 = 96        3 × 3 = 9     96 - 9 = 87

(unlucky jasmine she does not have enough paint )

8 0
3 years ago
Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations.
Anuta_ua [19.1K]

Answer:

c

Step-by-step explanation:

First, we can transform this into a matrix. The x coefficients will be the first ones for each row, the y coefficients the second column, etc.

\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right]

Next, we can define a reduced row echelon form matrix as follows:

With the leading entry being the first non zero number in the first row, the leading entry in each row must be 1. Next, there must only be 0s above and below the leading entry. After that, the leading entry of a row must be to the left of the leading entry of the next row. Finally, rows with all zeros should be at the bottom of the matrix.

Because there are 3 rows and we want to solve for 3 variables, making the desired matrix of form

\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] for the first three rows and columns. This would make the equation translate to

x= something

y= something

z = something, making it easy to solve for x, y, and z.

Going back to our matrix,

\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right] ,

we can start by removing the nonzero values from the first column for rows 2 and 3 to reach the first column of the desired matrix. We can do this by multiplying the first row by -6 and adding it to the second row, as well as multiplying the first row by -1 and adding it to the third row. This results in

\left[\begin{array}{cccc}1&-2&3&-2\\0&14&-16&-36\\0&6&0&-36\end{array}\right]

as our matrix. * Next, we can reach the second column of our desired matrix by first multiplying the second row by (2/14) and adding it to the first row as well as multiplying the second row by (-6/14) and adding it to the third row. This eliminates the nonzero values from all rows in the second column except for the second row. This results in

\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&14&-16&-36\\0&0&96/14&-288/14\end{array}\right]

After that, to reach the desired second column, we can divide the second row by 14, resulting in

\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&1&-16/14&-36/14\\0&0&96/14&-288/14\end{array}\right]

Finally, to remove the zeros from all rows in the third column outside of the third row, we can multiply the third row by (16/96) and adding it to the second row as well as multiplying the third row by (-10/96) and adding it to the first row. This results in

\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&96/14&-288/14\end{array}\right]

We can then divide the third row by -96/14 to reach the desired third column, making the reduced row echelon form of the matrix

\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&1&-3\end{array}\right]

Therefore,

x=-5

y=-6

z=-3

* we could also switch the second and third rows here to make the process a little simpler

3 0
3 years ago
Mr. Chiro drew a design for an outdoor kitchen. The food prep area will be on a rectangular platform made of concrete that is 5
vitfil [10]

Answer:

The volume of platform

= 11 ft³

Step-by-step explanation:

The height of the Platforms are

The food prep area  = 5 ft

Storage shelf = 6 ft

Side of rectangle = b width of platform = d

Therefore area of platform = b·d

Volume of the food prep area platform = Area × height = 5 b·d ft³

Volume of the storage shelf  platform = Area × height of storage shelf platform = 6 b·d ft³

Therefore the total volume = Volume of food storage platform + volume of storage shelf platform = 5 b·d ft³ + 6·b·d ft³ = 11·b·d ft³

8 0
3 years ago
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