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Elanso [62]
3 years ago
12

Easy "mean" question :)

Mathematics
2 answers:
Gnesinka [82]3 years ago
7 0

Answer:

Answer choice C

Step-by-step explanation:

Adding zero doesn't changed the sum, therefore doesn't change the median

lora16 [44]3 years ago
7 0

Answer:

C.

Step-by-step explanation:

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A tax assessor wants to assess the mean property tax bill for all homeowners in a certain state. From a survey ten years ago, a
Jet001 [13]

Answer:

The answer is below

Step-by-step explanation:

From the table, the mean (μ) = 1390.75 and the standard deviation (σ) = 518.75

The confidence level (C) = 90% = 0.9

α = 1 - C = 1 - 0.9 = 0.1

α/2 = 0.1 / 2 = 0.05

The z score of α/2 (0.05) is the same as the z score of 0.45 (0.5 - 0.05) which is equal to 1.645.

The margin of error (E) is given as:

E=Z_\frac{\alpha}{2}*\frac{\sigma}{\sqrt{n} }  \\\\E=1.645*\frac{518.75}{\sqrt{14} } =228.07

The confidence interval = μ ± E = 1390.75 ± 228.07 = (1162.68, 1618.82)

The confidence interval is between 1162.68 and 1618.82.

7 0
3 years ago
Abbie decides to start doing crunches as part of her daily workout. She decides to do 15 crunches the first day and then increas
Pavlova-9 [17]
For this case, the first thing we must do is define a variable.
 We have then:
 n: number of days.
 We now write the explicit formula that represents the problem.
 We have then:
 an = 4n + 15
 Where,
 15: crunches the first day
 4: increase the number 4 each day
 Answer:
 
An explicit formula for the number of crunches Abbie will do on day n is:
 
an = 4n + 15
3 0
3 years ago
99 POINT QUESTION, PLUS BRAINLIEST!!!
sattari [20]
We know, that the <span>area of the surface generated by revolving the curve y about the x-axis is given by:

\boxed{A=2\pi\cdot\int\limits_a^by\sqrt{1+\left(y'\right)^2}\, dx}

In this case a = 0, b = 15, y=\dfrac{x^3}{15} and:

y'=\left(\dfrac{x^3}{15}\right)'=\dfrac{3x^2}{15}=\boxed{\dfrac{x^2}{5}}

So there will be:

A=2\pi\cdot\int\limits_0^{15}\dfrac{x^3}{15}\cdot\sqrt{1+\left(\dfrac{x^2}{5}\right)^2}\, dx=\dfrac{2\pi}{15}\cdot\int\limits_0^{15}x^3\cdot\sqrt{1+\dfrac{x^4}{25}}\,\, dx=\left(\star\right)\\\\-------------------------------\\\\&#10;\int x^3\cdot\sqrt{1+\dfrac{x^4}{25}}\,\,dx=\int\sqrt{1+\dfrac{x^4}{25}}\cdot x^3\,dx=\left|\begin{array}{c}t=1+\dfrac{x^4}{25}\\\\dt=\dfrac{4x^3}{25}\,dx\\\\\dfrac{25}{4}\,dt=x^3\,dx\end{array}\right|=\\\\\\

=\int\sqrt{t}\cdot\dfrac{25}{4}\,dt=\dfrac{25}{4}\int\sqrt{t}\,dt=\dfrac{25}{4}\int t^\frac{1}{2}\,dt=\dfrac{25}{4}\cdot\dfrac{t^{\frac{1}{2}+1}}{\frac{1}{2}+1}= \dfrac{25}{4}\cdot\dfrac{t^{\frac{3}{2}}}{\frac{3}{2}}=\\\\\\=\dfrac{25\cdot2}{4\cdot3}\,t^\frac{3}{2}=\boxed{\dfrac{25}{6}\,\left(1+\dfrac{x^4}{25}\right)^\frac{3}{2}}\\\\-------------------------------\\\\

\left(\star\right)=\dfrac{2\pi}{15}\cdot\int\limits_0^{15}x^3\cdot\sqrt{1+\dfrac{x^4}{25}}\,\, dx=\dfrac{2\pi}{15}\cdot\dfrac{25}{6}\cdot\left[\left(1+\dfrac{x^4}{25}\right)^\frac{3}{2}\right]_0^{15}=\\\\\\=&#10;\dfrac{5\pi}{9}\left[\left(1+\dfrac{15^4}{25}\right)^\frac{3}{2}-\left(1+\dfrac{0^4}{25}\right)^\frac{3}{2}\right]=\dfrac{5\pi}{9}\left[2026^\frac{3}{2}-1^\frac{3}{2}\right]=\\\\\\=&#10;\boxed{\dfrac{5\Big(2026^\frac{3}{2}-1\Big)}{9}\pi}

Answer C.
</span>
3 0
3 years ago
Evaluate the following expressions, and justify your answers.<br> WhatPower7(49)
MaRussiya [10]

Answer:

whatpower7(49) = 2

Step-by-step explanation:

given data  

WhatPower7(49)

to find out

Evaluate the expressions WhatPower7(49)

solution

as we know that whatpower mean exponent of equation so we get by given equation  

we know whatpower7(49) = 2

because  

we know that  7 × 7 = 49  

so that 7² = 49

so that  the exponent  is here 2 for 7 that become 49

so correct answer is 2

6 0
3 years ago
Find the following measure for this figure.
ss7ja [257]

Answer: last option (5π√146 units²)

Step-by-step explanation:

To solve the exercise you must apply the formula for calculate the lateral area of a cone, which is shown below:

 LA=r*L*\pi

where r is the radius but L is the slant height.

As you can see in the figure attached:

r=5

But you need to find the slant height with the Pythagorean Theorem (L would be the hypotenuse):

L=\sqrt{11^2+5^2}=\sqrt{146}

Substitute into the formula, then:

 LA=(5)(\sqrt{146})\pi=5\pi\ \sqrt{146units²

4 0
3 years ago
Read 2 more answers
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