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jonny [76]
3 years ago
13

Nate borrowed $62,000 at 9.4% interest per year if he owed a total of $910.90 in when he repaid the loan how many days do they k

eep the money for
Mathematics
1 answer:
OverLord2011 [107]3 years ago
6 0
The formula for simple annual interest is:

I = Prt

where,

I = Interest accumulated = $910.90
P = Principal Amount = $62000
r = Interest rate = 9.4% = 0.094
t = time in years

Using the values in above equation, we get:

910.90 = 62000 x 0.094 x t

⇒ t = 910.90/(62000 x 0.094) = 0.156

This is the time in years. Since there are 365 days in a year, the time in days will be:

t = 0.156 x 365 = 57 (rounded to nearest day)

This means, Nate kept the borrowed money for 57 days
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Ivenika [448]
She spent $6.12 on the muffins for her and her friends, and she has $8.36 left on her gift card. By multiplying 6 by $1.02, you get the amount she spent, and by subtracting $14.48 by $6.12, I find how much she has left on her gift card.
8 0
2 years ago
Solve 5y'' + 3y' – 2y = 0, y(0) = 0, y'(0) = 2.8 y(t) = 0 Preview
mario62 [17]

Answer:  The required solution is

y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.

Step-by-step explanation:   We are given to solve the following differential equation :

5y^{\prime\prime}+3y^\prime-2y=0,~~~~~~~y(0)=0,~~y^\prime(0)=2.8~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let us consider that

y=e^{mt} be an auxiliary solution of equation (i).

Then, we have

y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.

Substituting these values in equation (i), we get

5m^2e^{mt}+3me^{mt}-2e^{mt}=0\\\\\Rightarrow (5m^2+3y-2)e^{mt}=0\\\\\Rightarrow 5m^2+3m-2=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow 5m^2+5m-2m-2=0\\\\\Rightarrow 5m(m+1)-2(m+1)=0\\\\\Rightarrow (m+1)(5m-1)=0\\\\\Rightarrow m+1=0,~~~~~5m-1=0\\\\\Rightarrow m=-1,~\dfrac{1}{5}.

So, the general solution of the given equation is

y(t)=Ae^{-t}+Be^{\frac{1}{5}t}.

Differentiating with respect to t, we get

y^\prime(t)=-Ae^{-t}+\dfrac{B}{5}e^{\frac{1}{5}t}.

According to the given conditions, we have

y(0)=0\\\\\Rightarrow A+B=0\\\\\Rightarrow B=-A~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

and

y^\prime(0)=2.8\\\\\Rightarrow -A+\dfrac{B}{5}=2.8\\\\\Rightarrow -5A+B=14\\\\\Rightarrow -5A-A=14~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{Uisng equation (ii)}]\\\\\Rightarrow -6A=14\\\\\Rightarrow A=-\dfrac{14}{6}\\\\\Rightarrow A=-\dfrac{7}{3}.

From equation (ii), we get

B=\dfrac{7}{3}.

Thus, the required solution is

y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.

7 0
3 years ago
(7x-3) ( 11y+5) what’s the value of x
timofeeve [1]

Answer:

7x - 3 = 60

7x = 63

 x = 9

if you need to find for y

11y + 5 = 60

11y = 55

   y = 5

Step-by-step explanation:

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7 0
3 years ago
Whats 234445x237=? fhrerjtiognmiovmenr
Naddika [18.5K]

Answer:

234445×237=55,563,465

5 0
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Answer:

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Step-by-step explanation:

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