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3 years ago

PLS HELP ASAP!! Which value of x makes 7 + 5(x - 3) = 22 a true statement? khan academy

Mathematics

2 answers:

Sladkaya [172]3 years ago

8 0

Answer:

x=6

Step-by-step explanation:

7 + 5(x - 3) = 22

The first step is to distribute the 5

7+ 5x-5*3 =22

7+ 5x-15 =22

Combine like terms

5x-8 =22

Add 8 to each side

5x-8+8 =22+8

5x = 30

5x/5 = 30/5

x=6

Mazyrski [523]3 years ago

6 0

Answer:

The Answer is c) 6

Step-by-step explanation:

Solve for x:

5 (x - 3) + 7 = 22

5 (x - 3) = 5 x - 15:

5 x - 15 + 7 = 22

Grouping like terms, 5 x - 15 + 7 = 5 x + (7 - 15):

5 x + (7 - 15) = 22

7 - 15 = -8:

5 x + -8 = 22

Add 8 to both sides:

5 x + (8 - 8) = 8 + 22

8 - 8 = 0:

5 x = 22 + 8

22 + 8 = 30:

5 x = 30

Divide both sides of 5 x = 30 by 5:

(5 x)/5 = 30/5

5/5 = 1:

x = 30/5

The gcd of 30 and 5 is 5, so 30/5 = (5×6)/(5×1) = 5/5×6 = 6:

Answer: x = 6

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Step-by-step explanation:

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3 years ago

7 measured data points have a sample mean of 1403 and a standard deviation of 27. Determine the best estimate of the mean value

mina [271]

Answer:

Step-by-step explanation:

Hello!

You have sample of n=7 with mean X[bar]= 1403 and standard deviation S=27 and are required to estimate the mean with a 95%CI.

Asuming this sample comes from a normal population I'll use a stuent t to estimate the interval (a sample of 7 units is too small for the standard normal to be accurate for the estimation):

[X[bar]± $t_{n-1;1-\alpha /2}$ * $\frac{S}{\sqrt{n} }$ ]

$t_{n-1;1-\alpha /2} = t_{6;0.975}= 2.365$

[1403±2.365* $\frac{27}{\sqrt{7} }$ ]

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The margin of error is the semiamplitude of the interval and you can calculate it as:

$d= \frac{Upbond-Lowbond}{2}= \frac{1427.13-1378.87}{2} = 24.13$

With a confidence level of 95% you'd expect that the real value of the mean is contained by the interval [1378.87;1427.13], the best estimate of the mean value is expected to be ± 24.13 of 1403.

I hope it helps!

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3 years ago

What is the recursive rule for the sequence?

babymother [125]

Answer:

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