Question

If the magnetic field is held constant at 3.0 T and the loop is pulled out of the region that contains the field in 0.2 s, what is the magnitude of the average induced emf in the loop

Answer 1

Answer:

emf = 15 * Area  and if A is given in square meters, the units of the emf will be Volts

Explanation:

Assuming that the area of the loop of current (A) is known, the magnitude of the induced emf can be calculated using Faraday-Lenz's Law:

$emf=|-\frac{\Delta\,\Phi}{\Delta \,t} |=|\frac{A\,B}{\Delta \,t}|=|\frac{A\,(3)}{0.2}|=15\,A$

and if the area (A) is given in square meters, the emf will directly come in units of Volts.