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Naddika [18.5K]
4 years ago
11

If the magnetic field is held constant at 3.0 T and the loop is pulled out of the region that contains the field in 0.2 s, what

is the magnitude of the average induced emf in the loop
Physics
1 answer:
kap26 [50]4 years ago
5 0

Answer:

emf = 15 * Area  and if A is given in square meters, the units of the emf will be Volts

Explanation:

Assuming that the area of the loop of current (A) is known, the magnitude of the induced emf can be calculated using Faraday-Lenz's Law:

emf=|-\frac{\Delta\,\Phi}{\Delta \,t} |=|\frac{A\,B}{\Delta \,t}|=|\frac{A\,(3)}{0.2}|=15\,A

and if the area (A) is given in square meters, the emf will directly come in units of Volts.

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